>> 双精度数组的运算符？

Posted 2023-02-16

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【中文标题】>> 双精度数组的运算符？【英文标题】：>> operator on array of doubles? 【发布时间】：2019-04-01 14:29:30 【问题描述】：

将数据输入数组的问题。

我正在使用 Dev C++ 执行和编译。下面是我的代码问题所在：

for (int k=0;k<=149;k++)                                               // k - scanning through Y within single file #i
        for (int l=0;l<=199;l++)                                           // l - scanning through X within single file #i
            inp >> X[l]>> Y[k]>> Z>> Mx[l][k]>> My[l][k]>> Mz[l][k];

Z 没有缺少下标，它就是这样设计的。

完整的错误代码：

[Error] no match for 'operator>>' (operand types are
'std::basic_istream<char>::__istream_type aka std::basic_istream<char>' and 'double [2]')

欢迎任何建议谢谢。

完整代码：

#pragma warning(disable:4786)
#include <cstdio>
#include <iostream>
#include <fstream>
#include <cstdlib>
#include <string>
#include <cstring>

using namespace std;
string filename(int filenumber);
int main () 

    char *flnmptr;
    string str,tmpr;
    char flnm[50];

                                    !!! make sure that the array dimensions for input data are right - that might screw the output files
                                    dimensions are written in the 2nd header line of the input file

    double X[150], Y[200], Z[2], Mx[150][200][2], My[150][200][2], Mz[100][100][2], time;                               // data from file 
    // double hX[5001], vY[5001], hMx[5001],hMy[5001],hMz[5001], vMx[5001], vMy[5001], vMz[5001]; // data to be written to file
    //int xcnt, ycnt;            // variable to count how many values will be written to a file
    const int N=600;             //number of files
    //const int ptN=20;          // number of points in the line
    const double timestep=1e-14; // time step of files
    const double X0=2.749313e-1;      // X coordinate of line to read into vertical stripe output
    const double Y0=-9.614638e-1;      // Y coordinate of line to read into horizontal stripe output

ofstream outp("SWstripeCoupledCorner50difference10_120GHz.txt");        //opening output file 
    if (!outp)
        cout << "Can't open file.\n";
        return 1;
    
    cout<<"Reading file #: ";

    outp.setf (ios::scientific ); // set the output format 

for (int i=1;i<=N;i++)
    std::strcpy(flnm,"");
    tmpr=filename(i);
    flnmptr=&tmpr[0];
    std::strcpy(flnm,flnmptr);

    ifstream inp;
    inp.open(flnm);                 // opens the file
    if(!inp)                        // if file couldn't be opened
     
        cerr << "Error: file could not be opened" << endl;
        exit(1);
    

    std::getline(inp,str,'\n');
    std::getline(inp,str,'\n');
    inp.setf (ios::scientific);

    for (int k=0;k<=149;k++)                                               // k - scanning through Y within single file #i
        for (int l=0;l<=199;l++)                                           // l - scanning through X within single file #i
            inp >> X[l]>> Y[k]>> Z>> Mx[l][k]>> My[l][k]>> Mz[l][k];

【问题讨论】：

请粘贴完整代码。 inp 是什么类型？ X、Y、Z、Mx、My、Mz 的具体类型是什么？请提供minimal reproducible example。从错误看来，您正在尝试使用operator>> 读取数组。没有这样的内置运算符，您应该考虑在循环中读取此类数组的元素。好的。我会发布完整的代码啊，我想我明白了。我将深入研究解释数组和循环的文献，并尝试应用于我的代码。谢谢。 【参考方案1】：

你说过