洛谷P2409Y的积木

Posted 2020-08-16 Absolutezero

这是一道dp……

f [ i ] [ j ] 表示前 i 组，总和为 j 时的方案数

f [ i ] [ j + a [ i ] [ k ] ] <-- f [ i - 1 ] [ j ]

 1 #include<cstdio>
 2 #include<cstring>
 3 #include<algorithm> 
 4 using namespace std;
 5 const int N=105,M=11000;
 6 int f[N][M],a[N][N],maxl[N],maxn,n,Q;
 7 int main(){
 8     maxn=0;
 9     scanf("%d %d",&n,&Q);
10     for (int i=1;i<=n;i++){
11         scanf("%d",&a[i][0]);
12         for (int j=1;j<=a[i][0];j++){
13             scanf("%d",&a[i][j]);
14             if (a[i][j]>maxl[i])
15                 maxl[i]=a[i][j];
16         }
17         maxn+=maxl[i];
18         sort(a[i]+1,a[i]+a[i][0]+1);
19     }
20     for (int i=1;i<=a[1][0];i++)
21         f[1][a[1][i]]++;//初始化不能赋成1 
22     for (int i=2;i<=n;i++)
23         for (int j=1;j<=maxn;j++){
24             if (!f[i-1][j])
25                 continue;
26             for (int k=1;k<=a[i][0];k++)
27                 f[i][j+a[i][k]]+=f[i-1][j];
28         }
29     int p=1,j=0;
30     while (p<=Q){
31         j++;
32         for (int i=1;i<=f[n][j];i++){
33             if (p>Q) return 0;
34             printf("%d ",j);
35             p++;
36         }
37     }
38     return 0;
39 }

STD