Topological Sor-207. Course Schedule

Posted 抒抒说

tags:

篇首语:本文由小常识网(cha138.com)小编为大家整理,主要介绍了Topological Sor-207. Course Schedule相关的知识,希望对你有一定的参考价值。

There are a total of n courses you have to take, labeled from 0 to n - 1.

Some courses may have prerequisites, for example to take course 0 you have to first take course 1, which is expressed as a pair: [0,1]

Given the total number of courses and a list of prerequisite pairs, is it possible for you to finish all courses?

For example:

2, [[1,0]]

There are a total of 2 courses to take. To take course 1 you should have finished course 0. So it is possible.

2, [[1,0],[0,1]]

There are a total of 2 courses to take. To take course 1 you should have finished course 0, and to take course 0 you should also have finished course 1. So it is impossible.

Note:

  1. The input prerequisites is a graph represented by a list of edges, not adjacency matrices. Read more about how a graph is represented.
  2. You may assume that there are no duplicate edges in the input prerequisites.
class Solution {
public:
    bool canFinish(int numCourses, vector<pair<int, int>>& prerequisites) {
        vector<vector<int>> graph(numCourses, vector<int>(0)); 
        vector<int> in(numCourses, 0); 
        for (auto a : prerequisites) { 
            graph[a.second].push_back(a.first);
            ++in[a.first];
        }
        queue<int> q; 
        for (int i = 0; i < numCourses; ++i) {
            if (in[i] == 0) q.push(i);
        }
        while (!q.empty()) {
            int t = q.front();
            q.pop();
            for (auto a : graph[t]) {
                --in[a];
                if (in[a] == 0) q.push(a);
            }
        }
        for (int i = 0; i < numCourses; ++i) {
            if (in[i] != 0) return false;
        }
        return true;
    }
};

 

以上是关于Topological Sor-207. Course Schedule的主要内容,如果未能解决你的问题,请参考以下文章

Topological Sort

4 - BFS & Topological Algorithm

PAT 1146 Topological Order

PAT 1146 Topological Order

1146 Topological Order (25分)

Topological Sort (25分)