结对项目—黄金点游戏

Posted 2020-10-10

程序步骤：

       开始游戏—>选择轮次—>选择玩家人数—>每个玩家输入其选择的0到100之间的整数—>得出黄金点G值—>得出比分

代码来源：两人合作编写

运行环境：windows

编译语言：C++

#include <iostream>
#include<math.h>
using namespace std;
void main()
{
int i, j, num, n, m, S[100], S2[100], S3[100] = { 0};
double S1[100], ave,sum,G;
double max, min;
cout << "==============欢迎进入黄金点游戏!=============" << endl;
cout << "============== 游戏规则 ==============" << endl;
cout << "=========n个玩家进行游戏=========" << endl;
cout << "==每人写一个0~100之间的整数 (不包括0或100)==" << endl;
cout << "===========G=n位玩家平均值avg*0.618==============" << endl;
cout << "======最高分(1): 提交数字最接近G值的玩家======" << endl;
cout << "=====最低分(-1):提交数字距离G值最远的玩家=====" << endl;
cout << "===========:其他所有玩家为0分============" << endl;
cout << "请输入游戏轮次!" << endl;
cin >> n;
cout << "请输入玩家人数:" << endl;
cin >> m;
for (i = 1; i <= n; i++)
{
sum = 0;
G = 0;
cout << "请输入0 到100之间的整数." << endl;
for (j = 1; j <= m; j++)
{
cout <<" 玩家" << j << " :请输入你的整数!" << endl;
cin >> num;
S[j] = num;
sum = sum + S[j];
}
ave = sum / num;
G = ave*0.618;
cout << "黄金点是G=" << G << endl;
for (j = 1; j <= m; j++)
{
S1[j] = abs(S[j] - G);
}
max = min = S1[1];
for (j = 1; j <= m; j++)
{
if (S1[j] >= max)
max = S1[j];
else if (S1[j] < min)
min = S1[j];
}
for (j = 1; j <= m; j++)
{
if (S1[j] == max)
S2[j] = -1;
else if (S1[j] == min)
S2[j] = 1;
else S2[j] = 0;

}
for (j = 1; j <= m; j++)
{
cout << "本轮分数" << "S2[" << j << "]=" << S2[j] << endl;
S3[j] = S3[j] + S2[j];
cout << "总分数 " << "S3[" << j << "]=" << S3[j] << endl;
}
}
system("pause"); //按任意键返回
}