hdu 1001 Sum Problem
Posted
tags:
篇首语:本文由小常识网(cha138.com)小编为大家整理,主要介绍了hdu 1001 Sum Problem相关的知识,希望对你有一定的参考价值。
Time Limit: 1000/500 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 480655 Accepted Submission(s):
121603
Problem Description
Hey, welcome to HDOJ(Hangzhou Dianzi University Online
Judge).
In this problem, your task is to calculate SUM(n) = 1 + 2 + 3 + ... + n.
In this problem, your task is to calculate SUM(n) = 1 + 2 + 3 + ... + n.
Input
The input will consist of a series of integers n, one
integer per line.
Output
For each case, output SUM(n) in one line, followed by a
blank line. You may assume the result will be in the range of 32-bit signed
integer.
Sample Input
1
100
Sample Output
1
5050
Author
DOOM III
#include <cstdio> int n; int main() { while(scanf("%d",&n)!=EOF) { if(n%2==1) printf("%d\n\n",(n/2)*(1+n)+(n/2)+1); else printf("%d\n\n",(n/2)*(1+n)); } }
以上是关于hdu 1001 Sum Problem的主要内容,如果未能解决你的问题,请参考以下文章