Hdu 1019 Least Common Multiple

Posted 2020-09-23 寂地沉

Least Common Multiple

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 52368    Accepted Submission(s): 19897

Problem Description

The least common multiple (LCM) of a set of positive integers is the smallest positive integer which is divisible by all the numbers in the set. For example, the LCM of 5, 7 and 15 is 105.

 

 

Input

Input will consist of multiple problem instances. The first line of the input will contain a single integer indicating the number of problem instances. Each instance will consist of a single line of the form m n1 n2 n3 ... nm where m is the number of integers in the set and n1 ... nm are the integers. All integers will be positive and lie within the range of a 32-bit integer.

 

 

Output

For each problem instance, output a single line containing the corresponding LCM. All results will lie in the range of a 32-bit integer.

 

 

Sample Input

2

3 5 7 15

6 4 10296 936 1287 792 1

 

 

Sample Output

105

10296

#include<stdio.h>
int gcd(int a,int b)//辗转相除求最大公约数 {
    if(b==0) return a;
    return gcd(b,a%b);
}
int main()
{
    int n,a,b,i,m;
    scanf("%d",&m);
    while(m--)
    {
        scanf("%d%d",&n,&a);
        for(i=1;i<n;i++)
        {
            scanf("%d",&b);
            a=a/gcd(a,b)*b;//最小公倍数等于两个数的乘积除以最大公约数         }
        printf("%d\n",a);
    }
    return 0;
}