洛谷 P2486 [SDOI2011]染色

Posted 弥生三月

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题目描述

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输入输出格式

输入格式:

 

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输出格式:

 

对于每个询问操作,输出一行答案。

 

输入输出样例

输入样例#1:
6 5
2 2 1 2 1 1
1 2
1 3
2 4
2 5
2 6
Q 3 5
C 2 1 1
Q 3 5
C 5 1 2
Q 3 5
输出样例#1:
3
1
2

说明

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题目大意:给一棵树,要求支持链覆盖+查询链上颜色段数

先考虑链上怎么做吧,颜色段数这个东西支持区间加,一个区间可以用三个属性表示:左端点的颜色,右端点的颜色,区间颜色段数

两段合并以后的颜色段数是:左段颜色段数+右段颜色段数-(左段右端点颜色==右段左端点颜色)

然后既然链上可以线段树,那树上直接树链剖分就好了

注意一下这个区间加是不满足交换律的,要交换的话需要取反,树剖查询到最后的时候要分类讨论一下

  1 #include <iostream>
  2 #include <cstdlib>
  3 #include <cstdio>
  4 #include <algorithm>
  5 #include <string>
  6 #include <cstring>
  7 #include <cmath>
  8 #include <map>
  9 #include <stack>
 10 #include <set>
 11 #include <vector>
 12 #include <queue>
 13 #include <time.h>
 14 #define eps 1e-7
 15 #define INF 0x3f3f3f3f
 16 #define MOD 1000000007
 17 #define rep0(j,n) for(int j=0;j<n;++j)
 18 #define rep1(j,n) for(int j=1;j<=n;++j)
 19 #define pb push_back
 20 #define set0(n) memset(n,0,sizeof(n))
 21 #define ll long long
 22 #define ull unsigned long long
 23 #define iter(i,v) for(edge *i=head[v];i;i=i->nxt)
 24 #define max(a,b) (a>b?a:b)
 25 #define min(a,b) (a<b?a:b)
 26 #define print_runtime printf("Running time:%.3lfs\n",double(clock())/1000.0)
 27 #define TO(j) printf(#j": %d\n",j);
 28 //#define OJ
 29 using namespace std;
 30 const int MAXINT = 100010;
 31 const int MAXNODE = 100010;
 32 const int MAXEDGE = 2 * MAXNODE;
 33 char BUF, *buf;
 34 int read() {
 35     char c = getchar(); int f = 1, x = 0;
 36     while (!isdigit(c)) { if (c == -) f = -1; c = getchar(); }
 37     while (isdigit(c)) { x = x * 10 + c - 0; c = getchar(); }
 38     return f * x;
 39 }
 40 char get_ch() {
 41     char c = getchar();
 42     while (!isalpha(c)) c = getchar();
 43     return c;
 44 }
 45 //------------------- Head Files ----------------------//
 46 int c[MAXINT],cl[MAXINT];
 47 struct node {
 48     int lb, rb;
 49     node *l, *r;
 50     int num, lc, rc, tag;
 51     void color(int c) {
 52         num = 1;
 53         lc = rc = tag = c;
 54     }
 55     void pushdown() {
 56         if (tag) {
 57             l->color(tag); r->color(tag);
 58             tag = 0;
 59         }
 60     }
 61     void pushup() {
 62         lc = l->lc; rc = r->rc;
 63         num = l->num + r->num - (l->rc == r->lc);
 64     }
 65     node() {
 66         lb = rb = num = lc = rc = tag = 0;
 67     }
 68 };
 69 struct seg {
 70     int lc, rc, num;
 71     seg() {}
 72     seg(int _lc, int _rc, int _num) : lc(_lc), rc(_rc), num(_num) {}
 73 };
 74 seg add(seg a, seg b) {
 75     if (a.lc == -1) return b;
 76     if (b.lc == -1) return a;
 77     seg ans;
 78     ans.lc = a.lc;
 79     ans.rc = b.rc;
 80     ans.num = a.num + b.num - (a.rc == b.lc);
 81     return ans;
 82 }
 83 struct SegTree {
 84     node mp[MAXINT * 4];
 85     node *root;
 86     int _cnt;
 87     SegTree() {
 88         _cnt = 0;
 89     }
 90     node *newnode(int l, int r) {
 91         node *p = &mp[_cnt++];
 92         p->lb = l;
 93         p->rb = r;
 94         return p;
 95     }
 96     void maketree(int lb, int rb, node *&p) {
 97         p = newnode(lb, rb);
 98         if (rb - lb > 1) {
 99             maketree(lb, (lb + rb) / 2, p->l);
100             maketree((lb + rb) / 2, rb, p->r);
101             p->pushup();
102         }
103         else {
104             p->lc = p->rc = c[lb];
105             p->num = 1;
106         }
107     }
108     void cover(int lb, int rb, int c, node *p) {
109         if (lb >= p->rb || rb <= p->lb) return;
110         if (lb <= p->lb && rb >= p->rb) { p->color(c); return; }
111         p->pushdown();
112         cover(lb, rb, c, p->l);
113         cover(lb, rb, c, p->r);
114         p->pushup();
115     }
116     seg query(int lb, int rb, node *p) {
117         if (lb >= p->rb || rb <= p->lb) return seg(-1, -1, -1);
118         if (lb <= p->lb && rb >= p->rb) return seg(p->lc, p->rc, p->num);
119         p->pushdown();
120         return add(query(lb, rb, p->l), query(lb, rb, p->r));
121     }
122 } st;
123 int n, m, fa[MAXINT], sz[MAXINT], top[MAXINT], dfn[MAXINT], cnt_dfn = 1, dep[MAXINT], cnt;
124 struct edge {
125     int u, v;
126     edge *nxt;
127     edge() {}
128     edge(int _u, int _v, edge *_nxt) : u(_u), v(_v), nxt(_nxt) {}
129 } mp[MAXINT * 2], *head[MAXINT];
130 void addedge(int u, int v) {
131     mp[cnt] = edge(u, v, head[u]);
132     head[u] = &mp[cnt++];
133     mp[cnt] = edge(v, u, head[v]);
134     head[v] = &mp[cnt++];
135 }
136 void dfs1(int p) {
137     sz[p] = 1;
138     iter(i, p) {
139         if (i->v == fa[p])continue;
140         fa[i->v] = p; dep[i->v] = dep[p] + 1;
141         dfs1(i->v);
142         sz[p] += sz[i->v];
143     }
144 }
145 void dfs2(int p) {
146     int mx = 0, gs = 0;
147     dfn[p] = cnt_dfn++;
148     iter(i, p) {
149         if (i->v == fa[p]) continue;
150         if (sz[i->v] > mx) {
151             mx = sz[i->v];
152             gs = i->v;
153         }
154     }
155     if (gs == 0) return;
156     top[gs] = top[p];
157     dfs2(gs);
158     iter(i, p) {
159         if (i->v == fa[p] || i->v == gs) continue;
160         top[i->v] = i->v;
161         dfs2(i->v);
162     }
163 }
164 seg trans(seg a) {
165     return seg(a.rc, a.lc, a.num);
166 }
167 void modify(int l, int r, int c) {
168     while (top[l] != top[r]) {
169         if (dep[top[l]] > dep[top[r]]) {
170             st.cover(dfn[top[l]], dfn[l]+1, c, st.root);
171             l = fa[top[l]];
172         }
173         else {
174             st.cover(dfn[top[r]], dfn[r]+1, c, st.root);
175             r = fa[top[r]];
176         }
177     }
178     st.cover(min(dfn[r], dfn[l]), max(dfn[r], dfn[l])+1, c, st.root);
179 }
180 int query(int l, int r) {
181     seg ansl(-1, -1, -1), ansr(-1, -1, -1);
182     while (top[l] != top[r]) {
183         if (dep[top[l]] > dep[top[r]]) {
184             ansl = add(st.query(dfn[top[l]], dfn[l]+1, st.root), ansl);
185             l = fa[top[l]];
186         }
187         else {
188             ansr = add(st.query(dfn[top[r]], dfn[r]+1, st.root), ansr);
189             r = fa[top[r]];
190         }
191     }
192     if (dep[l] > dep[r]) {
193         ansl = add(trans(ansr), add(st.query(dfn[r], dfn[l]+1, st.root), ansl));
194     }
195     else {
196         ansl = add(trans(ansl), add(st.query(dfn[l], dfn[r]+1, st.root), ansr));
197     }
198     return ansl.num;
199 }
200 void get_input();
201 void work();
202 int main() {
203     get_input();
204     work();
205     return 0;
206 }
207 void work() {
208     dfs1(1);
209     dfs2(1);
210     rep1(i, n) c[dfn[i]] = cl[i];
211     st.maketree(1, n + 1, st.root);
212     while (m--) {
213         char op = get_ch();
214         int u, v, c;
215         if (op == C) {
216             u = read(), v = read(), c = read();
217             modify(u, v, c);
218         }
219         else {
220             u = read(); v = read();
221             printf("%d\n", query(u, v));
222         }
223     }
224 }
225 void get_input() {
226     n = read(); m = read();
227     rep1(i, n) cl[i] = read();
228     rep0(i, n - 1) {
229         int u = read(), v = read();
230         addedge(u, v);
231     }
232 }

 



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