线程练习-吃馍馍

Posted 2020-09-09 lunawzh

学习线程，处理共享资源，要保证每个线程对资源是安全的，这里模拟一个吃馍馍的例子，用一个线程作生产者单独生成镆镆，再随机生成几个线程来模拟消费者吃馍馍，生产的馍馍为0后其消费者无法再吃到馍馍，只能等生产者生产馍馍。

 static Mutex m = new Mutex();
        static void Main(string[] args)
        {
            momo = new Momo();
            CreateMomo();
            for (int j = 0; j < new Random().Next(3); j++)
            {
                while (true)
                {

                    Consume();
                    Thread.Sleep(1000);
                }
            }
        }
        static Momo momo = null;
        static int i = 0;
        public async static void CreateMomo()
        {

            await Task.Run(async () =>
            {
                while (true)
                {

                    await Task.Delay(new Random().Next(2000));
                    m.WaitOne();

                    //生产Momo
                    momo.list.Add(new Momo(++i));

                    Console.WriteLine("生产一个MOmo,共有Momo：" + momo.Count);
                    m.ReleaseMutex();
                }
            });
        }

        public async static void Consume()
        {
            await Task.Run(async () =>
            {
                await Task.Delay(new Random().Next(20000));
                m.WaitOne();
                if (momo.Count <= 0)
                {
                    Console.WriteLine("无Momo，" + Thread.CurrentThread.ManagedThreadId + "没吃着");
                    m.ReleaseMutex();
                    return;
                }
                momo.list.RemoveAt(0);
                Console.WriteLine(Thread.CurrentThread.ManagedThreadId + "吃了一个,还剩" + momo.Count);
                m.ReleaseMutex();
            });
        }