492. Construct the Rectangle

Posted 2020-08-29

For a web developer, it is very important to know how to design a web page‘s size. So, given a specific rectangular web page’s area, your job by now is to design a rectangular web page, whose length L and width W satisfy the following requirements:

1. The area of the rectangular web page you designed must equal to the given target area.

2. The width W should not be larger than the length L, which means L >= W.

3. The difference between length L and width W should be as small as possible.

You need to output the length L and the width W of the web page you designed in sequence.

Example:

Input: 4
Output: [2, 2]
Explanation: The target area is 4, and all the possible ways to construct it are [1,4], [2,2], [4,1]. 
But according to requirement 2, [1,4] is illegal; according to requirement 3,  [4,1] is not optimal compared to [2,2]. So the length L is 2, and the width W is 2.

 

My solution:

 1     public int[] constructRectangle(int area) {
 2         //    Define an array of length 2.
 3         int[] arr = new int[2];
 4         
 5         //    Compute the square root of area.
 6         Double x = Math.sqrt(new Integer(area));
 7         int y = x.intValue();
 8         
 9         /*     Start a cycle from the square root to 1.
10          *     Divide area by i, fill in the arr if reminder is 0.
11          *  　  Return the first arr.
12          */
13         for(int i = y; i>=1 ; i--){
14             if(area%i == 0){
15                 arr[0] = area/i;
16                 arr[1] = i;
17                 break;
18             }
19         }
20         
21         return arr;
22     }