492. Construct the Rectangle
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For a web developer, it is very important to know how to design a web page‘s size. So, given a specific rectangular web page’s area, your job by now is to design a rectangular web page, whose length L and width W satisfy the following requirements:
1. The area of the rectangular web page you designed must equal to the given target area.
2. The width W should not be larger than the length L, which means L >= W.
3. The difference between length L and width W should be as small as possible.
You need to output the length L and the width W of the web page you designed in sequence.
Example:
Input: 4 Output: [2, 2] Explanation: The target area is 4, and all the possible ways to construct it are [1,4], [2,2], [4,1]. But according to requirement 2, [1,4] is illegal; according to requirement 3, [4,1] is not optimal compared to [2,2]. So the length L is 2, and the width W is 2.
Note:
- The given area won‘t exceed 10,000,000 and is a positive integer
- The web page‘s width and length you designed must be positive integers.
输入一个矩形的面积,输出矩形的长和宽,长和宽的差要尽可能的小,长必须>=宽
C++(289ms):
1 class Solution { 2 public: 3 vector<int> constructRectangle(int area) { 4 int min= 10000010 ; 5 int h,w; 6 vector<int> vec; 7 if (area==1){ 8 vec.push_back(1); 9 vec.push_back(1); 10 return vec; 11 } 12 13 for (int i = 1 ; i <area/2+1 ; i++){ 14 if (area%i!=0) 15 continue; 16 else { 17 if (area/i-i<min && area/i-i>=0){ 18 min = area/i-i; 19 h=area/i; 20 w=i; 21 } 22 } 23 } 24 25 vec.push_back(h); 26 vec.push_back(w); 27 return vec; 28 } 29 };
C++(3ms):
1 class Solution { 2 public: 3 vector<int> constructRectangle(int area) { 4 int h,w; 5 vector<int> vec; 6 int t = (int)sqrt(area); 7 while(area%t!=0){ 8 t--; 9 } 10 h = area/t; 11 w=t; 12 vec.push_back(h); 13 vec.push_back(w); 14 15 return vec; 16 } 17 };
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