POJ 1840 Eqs
Posted zaq19970105
tags:
篇首语:本文由小常识网(cha138.com)小编为大家整理,主要介绍了POJ 1840 Eqs相关的知识,希望对你有一定的参考价值。
题目链接:https://vjudge.net/problem/POJ-1840
题目大意
有以下方程:
$$
\sum_i = 1^5 a_i * x_i^3 = 0, a_i \in [-50, 50], x_i \in [-50, 0) \cup (0, -50], a_i 和 x_i 都是整数
$$
现给定 5 个参数 ai ,求方程有多少不同的解?
分析
直接枚举肯定超时,这时可以考虑移项,变成$\sum_i = 1^2 a_i * x_i^3 = \sum_i = 3^5 a_i * x_i^3$,这样全部枚举的复杂度就从 1004 降到 1002 + 1003了。
代码如下
1 #include <cmath> 2 #include <ctime> 3 #include <iostream> 4 #include <string> 5 #include <vector> 6 #include <cstdio> 7 #include <cstdlib> 8 #include <cstring> 9 #include <queue> 10 #include <map> 11 #include <unordered_map> 12 #include <set> 13 #include <algorithm> 14 #include <cctype> 15 #include <stack> 16 #include <deque> 17 #include <list> 18 #include <sstream> 19 using namespace std; 20 21 #define INIT() ios::sync_with_stdio(false);cin.tie(0);cout.tie(0); 22 #define Rep(i,n) for (int i = 0; i < (n); ++i) 23 #define For(i,s,t) for (int i = (s); i <= (t); ++i) 24 #define rFor(i,t,s) for (int i = (t); i >= (s); --i) 25 #define ForLL(i, s, t) for (LL i = LL(s); i <= LL(t); ++i) 26 #define rForLL(i, t, s) for (LL i = LL(t); i >= LL(s); --i) 27 #define foreach(i,c) for (__typeof(c.begin()) i = c.begin(); i != c.end(); ++i) 28 #define rforeach(i,c) for (__typeof(c.rbegin()) i = c.rbegin(); i != c.rend(); ++i) 29 30 #define pr(x) cout << #x << " = " << x << " " 31 #define prln(x) cout << #x << " = " << x << endl 32 33 #define LOWBIT(x) ((x)&(-x)) 34 35 #define ALL(x) x.begin(),x.end() 36 #define INS(x) inserter(x,x.begin()) 37 #define UNIQUE(x) x.erase(unique(x.begin(), x.end()), x.end()) 38 #define REMOVE(x, c) x.erase(remove(x.begin(), x.end(), c), x.end()); // 删去 x 中所有 c 39 #define TOLOWER(x) transform(x.begin(), x.end(), x.begin(),::tolower); 40 #define TOUPPER(x) transform(x.begin(), x.end(), x.begin(),::toupper); 41 42 #define ms0(a) memset(a,0,sizeof(a)) 43 #define msI(a) memset(a,inf,sizeof(a)) 44 #define msM(a) memset(a,-1,sizeof(a)) 45 46 #define MP make_pair 47 #define PB push_back 48 #define ft first 49 #define sd second 50 51 template<typename T1, typename T2> 52 istream &operator>>(istream &in, pair<T1, T2> &p) 53 in >> p.first >> p.second; 54 return in; 55 56 57 template<typename T> 58 istream &operator>>(istream &in, vector<T> &v) 59 for (auto &x: v) 60 in >> x; 61 return in; 62 63 64 template<typename T1, typename T2> 65 ostream &operator<<(ostream &out, const std::pair<T1, T2> &p) 66 out << "[" << p.first << ", " << p.second << "]" << "\n"; 67 return out; 68 69 70 inline int gc() 71 static const int BUF = 1e7; 72 static char buf[BUF], *bg = buf + BUF, *ed = bg; 73 74 if(bg == ed) fread(bg = buf, 1, BUF, stdin); 75 return *bg++; 76 77 78 inline int ri() 79 int x = 0, f = 1, c = gc(); 80 for(; c<48||c>57; f = c==‘-‘?-1:f, c=gc()); 81 for(; c>47&&c<58; x = x*10 + c - 48, c=gc()); 82 return x*f; 83 84 85 template<class T> 86 inline string toString(T x) 87 ostringstream sout; 88 sout << x; 89 return sout.str(); 90 91 92 inline int toInt(string s) 93 int v; 94 istringstream sin(s); 95 sin >> v; 96 return v; 97 98 99 //min <= aim <= max 100 template<typename T> 101 inline bool BETWEEN(const T aim, const T min, const T max) 102 return min <= aim && aim <= max; 103 104 105 typedef long long LL; 106 typedef unsigned long long uLL; 107 typedef pair< double, double > PDD; 108 typedef pair< int, int > PII; 109 typedef pair< int, PII > PIPII; 110 typedef pair< string, int > PSI; 111 typedef pair< int, PSI > PIPSI; 112 typedef set< int > SI; 113 typedef set< PII > SPII; 114 typedef vector< int > VI; 115 typedef vector< double > VD; 116 typedef vector< VI > VVI; 117 typedef vector< SI > VSI; 118 typedef vector< PII > VPII; 119 typedef map< int, int > MII; 120 typedef map< LL, int > MLLI; 121 typedef map< int, string > MIS; 122 typedef map< int, PII > MIPII; 123 typedef map< PII, int > MPIII; 124 typedef map< string, int > MSI; 125 typedef map< string, string > MSS; 126 typedef map< PII, string > MPIIS; 127 typedef map< PII, PII > MPIIPII; 128 typedef multimap< int, int > MMII; 129 typedef multimap< string, int > MMSI; 130 //typedef unordered_map< int, int > uMII; 131 typedef pair< LL, LL > PLL; 132 typedef vector< LL > VL; 133 typedef vector< VL > VVL; 134 typedef priority_queue< int > PQIMax; 135 typedef priority_queue< int, VI, greater< int > > PQIMin; 136 const double EPS = 1e-8; 137 const LL inf = 0x3fffffff; 138 const LL infLL = 0x3fffffffffffffffLL; 139 const LL mod = 1e9 + 7; 140 const int maxN = 1e5 + 7; 141 const LL ONE = 1; 142 const LL evenBits = 0xaaaaaaaaaaaaaaaa; 143 const LL oddBits = 0x5555555555555555; 144 145 int a[6], ans; 146 VI v3; 147 MII H; 148 149 int main() 150 //freopen("MyOutput.txt","w",stdout); 151 //freopen("input.txt","r",stdin); 152 INIT(); 153 For(i, 1, 5) cin >> a[i]; 154 155 For(i, -50, -1) v3.PB(i * i * i); 156 For(i, 1, 50) v3.PB(i * i * i); 157 158 For(i, 0, 99) 159 For(j, 0, 99) 160 ++H[-a[1] * v3[i] - a[2] * v3[j]]; 161 162 For(i, 0, 99) 163 For(j, 0, 99) 164 For(k, 0, 99) 165 int ret = a[3] * v3[i] + a[4] * v3[j] + a[5] * v3[k]; 166 if(H.find(ret) != H.end()) ans += H[ret]; 167 168 169 cout << ans << endl; 170 return 0; 171
以上是关于POJ 1840 Eqs的主要内容,如果未能解决你的问题,请参考以下文章