[Codeplus 2017] 晨跑

Posted 2020-12-30 evenbao

[题目链接]

         https://www.lydsy.com/JudgeOnline/problem.php?id=5105

[算法]

        答案为三个数的最小公倍数

[代码]

       

#include<bits/stdc++.h>
using namespace std;

long long gcd(long long a,long long b)
{
    if (b == 0) return a;
    else return gcd(b,a % b);
}

int main()
{
    
    long long a,b,c;
    scanf("%lld%lld%lld",&a,&b,&c);
    long long d = a * b / gcd(a,b);
    printf("%lld
",c * d / gcd(c,d));
    
    return 0;
}