LeetCode（剑指 Offer）- 46. 把数字翻译成字符串

Posted 2022-04-15 放羊的牧码

题目链接：点击打开链接

题目大意：略。

解题思路

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AC 代码

• Java

// 解决方案(1)
class Solution 
    public int translateNum(int num) 
        String s = String.valueOf(num);
        int a = 1, b = 1;
        for(int i = 2; i <= s.length(); i++) 
            String tmp = s.substring(i - 2, i);
            int c = tmp.compareTo("10") >= 0 && tmp.compareTo("25") <= 0 ? a + b : a;
            b = a;
            a = c;
        
        return a;
    


// 解决方案(2)
class Solution 
    public int translateNum(int num) 
        String s = String.valueOf(num);
        int a = 1, b = 1;
        for(int i = s.length() - 2; i > -1; i--) 
            String tmp = s.substring(i, i + 2);
            int c = tmp.compareTo("10") >= 0 && tmp.compareTo("25") <= 0 ? a + b : a;
            b = a;
            a = c;
        
        return a;
    


// 解决方案(3)
class Solution 
    public int translateNum(int num) 
        int a = 1, b = 1, x, y = num % 10;
        while(num > 9) 
            num /= 10;
            x = num % 10;
            int tmp = 10 * x + y;
            int c = (tmp >= 10 && tmp <= 25) ? a + b : a;
            b = a;
            a = c;
            y = x;
        
        return a;
    

• C++

// 解决方案(1)
class Solution 
public:
    int translateNum(int num) 
        int a = 1, b = 1, x, y = num % 10;
        while(num > 9) 
            num /= 10;
            x = num % 10;
            int tmp = 10 * x + y;
            int c = (tmp >= 10 && tmp <= 25) ? a + b : a;
            b = a;
            a = c;
            y = x;
        
        return a;
    
;

// 解决方案(2)
class Solution 
public:
    int translateNum(int num) 
        string s = to_string(num);
        int a = 1, b = 1, len = s.size();
        for(int i = 2; i <= len; i++) 
            string tmp = s.substr(i - 2, 2);
            int c = tmp.compare("10") >= 0 && tmp.compare("25") <= 0 ? a + b : a;
            b = a;
            a = c;
        
        return a;
    
;

// 解决方案(3)
class Solution 
public:
    int translateNum(int num) 
        string s = to_string(num);
        int a = 1, b = 1, len = s.size();
        for(int i = len - 2; i > -1; i--) 
            string tmp = s.substr(i, 2);
            int c = tmp.compare("10") >= 0 && tmp.compare("25") <= 0 ? a + b : a;
            b = a;
            a = c;
        
        return a;
    
;