026.阿拉伯数字转换为罗马数字

Posted 2022-04-28 程序员编程指南

#include <stdio.h>
#define ROWS 4
#define COLS 4
int nums[ROWS][COLS]=1000,1000,1000,1000,
		         900,500,400,100,
		         90,50,40,10,
		         9,5,4,1;
char *roms[ROWS][COLS]="m","m","m","m",
		              "cm","d","cd","c",
		              "xc","l","xl","x",
		              "ix","v","iv","i";

main(int argc,char *argv[ ])

	int low,high;
	char roman[25];

	if(argc<2)
		printf("Usage:roman decimal_number\\n");/*运行程序需带整数参数*/
	 	exit(0);
	
	high=low=atoi(argv[1]);/*将第一个参数转换成整数*/
	checknum(low);
	if(argc>2)
	/*带两个参数*/
	high=atoi(argv[2]);
	checknum(high);
	if(low>high)
		
			low=high;
			high=atoi(argv[1]);
		
	
	else
		low=1;
	for(;low<=high;low++)
	
		to_roman(low,roman);
		printf("%d\\t%s\\n",low,roman);
	


checknum(int val)/*检查参数合理性*/

	if(val<1||val>9999)
	
		printf("The number must be in range 1..9999.\\n");
		exit(0);
	

to_roman(int decimal,char roman[ ])/*将整数转换成罗马数字表示*/

	int power,index;
	roman[0]='\\0';
	for(power=0;power<ROWS;power++)
		for(index=0;index<COLS;index++)
			while(decimal>=nums[power][index])
			
				strcat(roman,roms[power][index]);
				decimal-=nums[power][index];