sh 项目欧拉1

Posted 2021-05-06

sum=0;(seq 5 5 999 && seq 3 3 999) | sort -h | uniq | while read n; do sum=$(( $sum + $n )); echo $sum; done
(seq 5 5 999 ; seq 3 3 999) | sort -h | uniq | jq -s add

#uniq <(sort -h <(z seq 3 3 999) <(z seq 5 5 999))
jq -s add <(uniq <(sort -h <(z seq 3 3 999) <(z seq 5 5 999)))