无法在 org.hibernate.mapping.Table(user_details) 及其相关的超级表和辅助表中找到具有逻辑名称的列：user_details_id

Posted 2023-02-26

【中文标题】无法在 org.hibernate.mapping.Table(user_details) 及其相关的超级表和辅助表中找到具有逻辑名称的列：user_details_id

【英文标题】：Unable to find column with logical name: user_details_id in org.hibernate.mapping.Table(user_details) and its related supertables and secondary tables

【发布时间】：2019-08-17 14:54:42

【问题描述】：

我正在尝试创建简单的单向映射。我正在使用 MappedSuperclass 和 @JoinColumn 可能有问题。看起来实体无法从超类中找到 id 字段。

例外：

Caused by: org.hibernate.MappingException: Unable to find column with logical name: user_details_id in org.hibernate.mapping.Table(user_details) and its related supertables and secondary tables
    at org.hibernate.cfg.Ejb3JoinColumn.checkReferencedColumnsType(Ejb3JoinColumn.java:832) ~[hibernate-core-5.3.7.Final.jar:5.3.7.Final]
    at org.hibernate.cfg.BinderHelper.createSyntheticPropertyReference(BinderHelper.java:256) ~[hibernate-core-5.3.7.Final.jar:5.3.7.Final]
    at org.hibernate.cfg.ToOneFkSecondPass.doSecondPass(ToOneFkSecondPass.java:101) ~[hibernate-core-5.3.7.Final.jar:5.3.7.Final]
    at org.hibernate.boot.internal.InFlightMetadataCollectorImpl.processEndOfQueue(InFlightMetadataCollectorImpl.java:1827) ~[hibernate-core-5.3.7.Final.jar:5.3.7.Final]
    at org.hibernate.boot.internal.InFlightMetadataCollectorImpl.processFkSecondPassesInOrder(InFlightMetadataCollectorImpl.java:1771) ~[hibernate-core-5.3.7.Final.jar:5.3.7.Final]
    at org.hibernate.boot.internal.InFlightMetadataCollectorImpl.processSecondPasses(InFlightMetadataCollectorImpl.java:1658) ~[hibernate-core-5.3.7.Final.jar:5.3.7.Final]
    at org.hibernate.boot.model.process.spi.MetadataBuildingProcess.complete(MetadataBuildingProcess.java:287) ~[hibernate-core-5.3.7.Final.jar:5.3.7.Final]
    at org.hibernate.jpa.boot.internal.EntityManagerFactoryBuilderImpl.metadata(EntityManagerFactoryBuilderImpl.java:904) ~[hibernate-core-5.3.7.Final.jar:5.3.7.Final]
    at org.hibernate.jpa.boot.internal.EntityManagerFactoryBuilderImpl.build(EntityManagerFactoryBuilderImpl.java:935) ~[hibernate-core-5.3.7.Final.jar:5.3.7.Final]

超类：

@Getter
@Setter
@MappedSuperclass
public abstract class BaseEntity 

    @Id
    @GeneratedValue(
            strategy =  GenerationType.IDENTITY
    )
    private Long id;

消息实体（连接发送方和接收方的 id）

@Getter
@Setter
@NoArgsConstructor
@AllArgsConstructor
@Builder
@Entity(name = "Message")
@Table(name = "message")
public class Message extends BaseEntity 
    private String title;
    private String details;
    private String message_container;
    private LocalDate dataOfSending;

    @ManyToOne(optional = false)
    @JoinColumn(name = "sender_id", referencedColumnName = "user_details_id")
    private UserDetails sender;

    @ManyToOne(optional = false)
    @JoinColumn(name = "receiver_id", referencedColumnName = "user_details_id")
    private UserDetails receiver;

用户详细信息（不应该知道消息）

@Getter
@Setter
@Builder
@NoArgsConstructor
@AllArgsConstructor
@Entity(name = "UserDetails")
@Table(name = "user_details")
public class UserDetails extends BaseEntity 

    private String firstName;
    private String lastName;
    private String motherName;
    private String fatherName;
    private String personalIdentityNum;
    private LocalDate dateOfBirth;

    @OneToOne
    @JoinColumn(name = "user_id")
    private User user;

    @OneToOne(mappedBy = "userDetails")
    private Address address;

    @OneToOne(mappedBy = "userDetails")
    private Contact contact;

    @OneToOne(mappedBy = "userDetails")
    private ProfileImage profileImage;

有什么想法吗？提前谢谢你。

【问题讨论】：

你能检查我的答案吗？

【参考方案1】：

不确定它是否能解决您的问题，但我刚刚遇到了同样的问题。 诀窍是在 SpringBoot 中，您必须引用 logical id，而不是 db 列名。

我的情况：

PlayerEntity 具有 playerId，它生成名为 player_id 的列。这是@NaturalId。

在另一个实体中，我写了一个@ManyToOne，设置referencedColumnName = "player_id"失败：

[org/springframework/boot/autoconfigure/orm/jpa/HibernateJpaConfiguration.class]: Invocation of init method failed; nested exception is org.hibernate.MappingException: Unable to find column with logical name: player_id in org.hibernate.mapping.Table(player) and its related supertables and secondary tables

由于是“逻辑名称”，我尝试将player_id 更改为playerId（PlayerEntity 中的字段名称，现在一切正常：

    @ManyToOne
//    @JoinColumn(name = "player_id", referencedColumnName = "player_id") // fails
    @JoinColumn(name = "player_id", referencedColumnName = "playerId") // works! What the...
    private PlayerEntity player;

这可行，生成具有正确 FK 的列：

    constraint FK6aw598iko4dicfrfa6sj0mni1
        foreign key (player_id) references player (player_id)

这实际上看起来像是 Spring JPA 或 Hibernate 中的一个错误。数据库是 mysql 8.1。

【参考方案2】：

你能改变Message类中的这个部分吗

   @ManyToOne(optional = false)
    @JoinColumn(name = "sender_id", referencedColumnName = "user_details_id")
    private UserDetails sender;

    @ManyToOne(optional = false)
    @JoinColumn(name = "receiver_id", referencedColumnName = "user_details_id")
    private UserDetails receiver;

到

    @ManyToOne
    @JoinColumn(name = "sender_id")
    private UserDetails sender;

    @ManyToOne
    @JoinColumn(name = "receiver_id")
    private UserDetails receiver;

并在UserDetails 中添加这些代码

 @OneToMany(mappedBy = "sender")
private List<Message> senderMessage = new ArrayList<>();

@OneToMany(mappedBy = "receiver")
private List<Message> receiverMessage = new ArrayList<>();

【讨论】：

嗨。是的，这是一种可能的解决方案，但我只是想如果没有 UserDetails 上的映射就可以实现这一点

实际上代码可以在没有在 UserDetails 端指定映射的情况下工作。但为什么？用户详情中没有映射的情况下如何找到sender_id？