如何在基于 webhook 和角色的 JS 中修复复杂的 Discord 命令

Posted 2023-03-14

【中文标题】如何在基于 webhook 和角色的 JS 中修复复杂的 Discord 命令

【英文标题】：How to fix a complex Discord command in JS based off of webhooks and roles

【发布时间】：2019-09-10 05:06:19

【问题描述】：

我正在处理一个命令，当你执行命令时，d!woa 会发生以下情况

使用特定名称创建一个 webhook，然后使用通道名称创建一个角色，之后机器人会监视该通道是否存在具有该特定名称的 webhook，并查看是否有人在该通道中发送消息.如果是这样，那么机器人将添加具有特定名称的角色。 问题是有这个错误：TypeError: Cannot read property 'guild' of undefined 该错误很可能出现在所提供代码的末尾。

我尝试重新排列代码、定义公会和定义消息。即使尝试了所有这些，它似乎也不起作用。我只希望它依赖 ID 而不是 Name 来准确执行此命令。

const Discord = require('discord.js');
const commando = require('discord.js-commando');

class woa extends commando.Command 

    constructor(client) 
        super(client, 
            name: 'watchoveradd',
            group: 'help',
            memberName: 'watchoveradd',
            description: 'placeholder',
            aliases: ['woa'],
        )
    
async run(message, args)

if (message.channel instanceof Discord.DMChannel) return message.channel.send('This command cannot be executed here.')
else

if(!message.member.guild.me.hasPermission(['MANAGE_WEBHOOKS'])) return message.channel.send('I don\'t have the permissions to make webhooks, please contact an admin or change my permissions!')
if(!message.member.guild.me.hasPermission(['MANAGE_ROLES'])) return message.channel.send('I don\'t have the permissions to make roles, please contact an admin or change my permissions!')
if (!message.member.hasPermission(['MANAGE_WEBHOOKS'])) return message.channel.send('You need to be an admin or webhook manager to use this command.')
if (!message.member.hasPermission(['MANAGE_ROLES'])) return message.channel.send('You need to be an admin or role manager to use this command.')

const avatar = `https://cdn.discordapp.com/attachments/515307677656678420/557050444954992673/Generic5.png`;
const name2 = "SYNTHIBUTWORSE-1.0WOCMD";

let woaID = message.mentions.channels.first(); 
if(!woaID) return message.channel.send("Channel is nonexistant or command was not formatted properly. Please do s!woa #(channelname)"); 
let specifiedchannel = message.guild.channels.find(t => t.id == woaID.id);; 
specifiedchannel.send('test');

const hook = await woaID.createWebhook(name2, avatar).catch(error => console.log(error))
await hook.edit(name2, avatar).catch(error => console.log(error))
message.channel.send("Please do not tamper with the webhook or else the command implied before will no longer function with this channel.")

setTimeout(function()
    message.channel.send('Please wait...');
  , 10);
setTimeout(function()
var role = message.guild.createRole(
    name: `Synthibutworse marker $woaID.name v1.0`,
    color: 0xcc3b3b,).catch(console.error);

if(role.name == "Synthibutworse marker") 
  role.setMentionable(false, 'SBW Ping Set.')
  role.setPosition(10)
  role.setPermissions(['CREATE_INSTANT_INVITE', 'SEND_MESSAGES'])
    .then(role => console.log(`Edited role`))
    .catch(console.error);
, 20);

var sbwrID = member.guild.roles.find(`Synthibutworse marker $woaID v1.0`);
let specifiedrole = message.guild.roles.find(r => r.id == sbwrID.id)

setTimeout(function()
      message.channel.send('Created Role... Please wait.');
, 100);

message.guild.specifiedchannel.replacePermissionOverwrites(
  overwrites: [
    
       id: specifiedrole,
       denied: ['SEND_MESSAGES'],
       allowed: ['VIEW_CHANNEL'],
    ,
  ],
    reason: 'Needed to change permissions'
  );

var member = client.user

var bot = message.client
bot.on('message', function(message)  
    if(message.channel.id == sbwrID.id) 
let bannedRole = message.guild.roles.find(role => role.id === specifiedrole);
message.member.addRole(bannedRole);
  
)

;
module.exports = woa;

我期望一个没有 TypeError 的命令，并且该命令能够创建一个角色和一个 webhook（用于标记），并且该角色是自动设置的，因此拥有该角色的用户将无法发言频道，在频道中发言的人将获得该角色。 实际输出是 TypeError: Cannot read property 'guild' of undefined，但创建了一个角色和 webhook。

【参考方案1】：

你有var sbwrID = member.guild... 您没有定义成员。使用message.member.guild...

您可以设置一个 linter (https://discordjs.guide/preparations/setting-up-a-linter.html) 来自动发现这些问题。

【讨论】：

这行得通，但在此之后出现了另一个问题。现在是Error: Value must be specified.

如果您可以获得堆栈跟踪信息会有所帮助