如何生成周表并按天和小时拆分
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【中文标题】如何生成周表并按天和小时拆分【英文标题】：How to Generate a Week Table and Split by Day and Hour 【发布时间】：2015-11-30 13:23:42 【问题描述】：首先，要明确；有一个这样的例子：
我可以通过这个查询获得课程：
$qb
->select("c")
->from("ATLReservationBundle:Course", "c")
->where("WEEK(c.courseDate, 1) = WEEK(CURRENT_DATE(), 1)")
->orderBy("c.courseDate", "ASC");
查询结果：
"courses": [
"id": 110,
"name": "Pilates",
"quota": 8,
"course_date": "2015-08-31T12:15:00+0000",
"studio":
"id": 2,
"name": "Stüdyo 2"
,
"trainer":
"id": 1,
"name": "-"
,
"id": 135,
"name": "Spinning",
"quota": 8,
"course_date": "2015-08-31T19:30:00+0000",
"studio":
"id": 2,
"name": "Stüdyo 2"
,
"trainer":
"id": 1,
"name": "-"
,
"id": 154,
"name": "Kick Box",
"quota": 6,
"course_date": "2015-08-31T20:00:00+0000",
"studio":
"id": 1,
"name": "Stüdyo 1"
,
"trainer":
"id": 1,
"name": "-"
,
"id": 133,
"name": "Spinning",
"quota": 8,
"course_date": "2015-09-01T12:15:00+0000",
"studio":
"id": 2,
"name": "Stüdyo 2"
,
"trainer":
"id": 1,
"name": "-"
,
"id": 113,
"name": "Crunch 30 Min.",
"quota": 8,
"course_date": "2015-09-01T18:30:00+0000",
"studio":
"id": 2,
"name": "Stüdyo 2"
,
"trainer":
"id": 1,
"name": "-"
,
"id": 112,
"name": "Pilates",
"quota": 8,
"course_date": "2015-09-01T19:00:00+0000",
"studio":
"id": 2,
"name": "Stüdyo 2"
,
"trainer":
"id": 1,
"name": "-"
,
"id": 150,
"name": "Spinning",
"quota": 8,
"course_date": "2015-09-01T19:30:00+0000",
"studio":
"id": 2,
"name": "Stüdyo 2"
,
"trainer":
"id": 1,
"name": "-"
,
"id": 136,
"name": "TRX Group",
"quota": 5,
"course_date": "2015-09-01T20:00:00+0000",
"studio":
"id": 2,
"name": "Stüdyo 2"
,
"trainer":
"id": 1,
"name": "-"
,
"id": 159,
"name": "Pilates",
"quota": 8,
"course_date": "2015-09-02T10:00:00+0000",
"studio":
"id": 2,
"name": "Stüdyo 2"
,
"trainer":
"id": 1,
"name": "-"
,
"id": 156,
"name": "Stretching",
"quota": 7,
"course_date": "2015-09-02T18:30:00+0000",
"studio":
"id": 2,
"name": "Stüdyo 2"
,
"trainer":
"id": 1,
"name": "-"
,
"id": 127,
"name": "Zumba",
"quota": 6,
"course_date": "2015-09-02T19:00:00+0000",
"studio":
"id": 1,
"name": "Stüdyo 1"
,
"trainer":
"id": 1,
"name": "-"
,
"id": 148,
"name": "Kick Box",
"quota": 6,
"course_date": "2015-09-02T20:00:00+0000",
"studio":
"id": 1,
"name": "Stüdyo 1"
,
"trainer":
"id": 1,
"name": "-"
,
"id": 138,
"name": "Crunch 30 Min.",
"quota": 8,
"course_date": "2015-09-03T12:15:00+0000",
"studio":
"id": 1,
"name": "Stüdyo 1"
,
"trainer":
"id": 1,
"name": "-"
,
"id": 121,
"name": "Pilates",
"quota": 8,
"course_date": "2015-09-03T19:00:00+0000",
"studio":
"id": 2,
"name": "Stüdyo 2"
,
"trainer":
"id": 1,
"name": "-"
,
"id": 117,
"name": "TRX",
"quota": 8,
"course_date": "2015-09-03T20:00:00+0000",
"studio":
"id": 2,
"name": "Stüdyo 2"
,
"trainer":
"id": 1,
"name": "-"
,
"id": 131,
"name": "Spinning",
"quota": 8,
"course_date": "2015-09-03T20:00:00+0000",
"studio":
"id": 2,
"name": "Stüdyo 2"
,
"trainer":
"id": 1,
"name": "-"
,
"id": 142,
"name": "Pilates",
"quota": 8,
"course_date": "2015-09-04T12:15:00+0000",
"studio":
"id": 2,
"name": "Stüdyo 2"
,
"trainer":
"id": 1,
"name": "-"
,
"id": 147,
"name": "LBT 30 min.",
"quota": 8,
"course_date": "2015-09-04T19:00:00+0000",
"studio":
"id": 1,
"name": "Stüdyo 1"
,
"trainer":
"id": 1,
"name": "-"
,
"id": 141,
"name": "Crunch 30 Min.",
"quota": 8,
"course_date": "2015-09-04T19:30:00+0000",
"studio":
"id": 2,
"name": "Stüdyo 2"
,
"trainer":
"id": 1,
"name": "-"
,
"id": 130,
"name": "Crunch 30 Min.",
"quota": 8,
"course_date": "2015-09-05T14:00:00+0000",
"studio":
"id": 2,
"name": "Stüdyo 2"
,
"trainer":
"id": 1,
"name": "-"
]
但我想将这些数据分组；
DAY - 31
HOUR - 12:15 > Coursename
HOUR - 19:30 > Coursename
DAY - 01
HOUR - 10:00...
我不知道该怎么做，有人吗？
更新
新查询：
$qb
->select("c, HOUR(c.courseDate) as hour, DAY(c.courseDate) as day")
->from("ATLReservationBundle:Course", "c")
->where("WEEK(c.courseDate, 1) = WEEK(CURRENT_DATE(), 1)")
->orderBy("c.courseDate", "ASC")
->groupBy("hour, day");
但是;此查询存在问题，我无法按HOUR(c.courseDate), DAY(c.courseDate) 分组，因为我收到此错误：
错误：无法按未定义的标识或结果变量分组。
所以，我在选择区域中将小时和天定义为变量。 我不想将日期和时间视为不同的变量。
查询结果：
"courses": [
"0":
"id": 110,
"name": "Pilates",
"quota": 8,
"course_date": "2015-08-31T12:15:00+0000",
"studio":
"id": 2,
"name": "Stüdyo 2"
,
"trainer":
"id": 1,
"name": "-"
,
"hour": "12",
"day": "31"
,
"0":
"id": 135,
"name": "Spinning",
"quota": 8,
"course_date": "2015-08-31T19:30:00+0000",
"studio":
"id": 2,
"name": "Stüdyo 2"
,
"trainer":
"id": 1,
"name": "-"
,
"hour": "19",
"day": "31"
,
"0":
"id": 154,
"name": "Kick Box",
"quota": 6,
"course_date": "2015-08-31T20:00:00+0000",
"studio":
"id": 1,
"name": "Stüdyo 1"
,
"trainer":
"id": 1,
"name": "-"
,
"hour": "20",
"day": "31"
,
"0":
"id": 133,
"name": "Spinning",
"quota": 8,
"course_date": "2015-09-01T12:15:00+0000",
"studio":
"id": 2,
"name": "Stüdyo 2"
,
"trainer":
"id": 1,
"name": "-"
,
"hour": "12",
"day": "1"
,
"0":
"id": 113,
"name": "Crunch 30 Min.",
"quota": 8,
"course_date": "2015-09-01T18:30:00+0000",
"studio":
"id": 2,
"name": "Stüdyo 2"
,
"trainer":
"id": 1,
"name": "-"
,
"hour": "18",
"day": "1"
,
"0":
"id": 112,
"name": "Pilates",
"quota": 8,
"course_date": "2015-09-01T19:00:00+0000",
"studio":
"id": 2,
"name": "Stüdyo 2"
,
"trainer":
"id": 1,
"name": "-"
,
"hour": "19",
"day": "1"
,
"0":
"id": 136,
"name": "TRX Group",
"quota": 5,
"course_date": "2015-09-01T20:00:00+0000",
"studio":
"id": 2,
"name": "Stüdyo 2"
,
"trainer":
"id": 1,
"name": "-"
,
"hour": "20",
"day": "1"
,
"0":
"id": 159,
"name": "Pilates",
"quota": 8,
"course_date": "2015-09-02T10:00:00+0000",
"studio":
"id": 2,
"name": "Stüdyo 2"
,
"trainer":
"id": 1,
"name": "-"
,
"hour": "10",
"day": "2"
,
"0":
"id": 156,
"name": "Stretching",
"quota": 7,
"course_date": "2015-09-02T18:30:00+0000",
"studio":
"id": 2,
"name": "Stüdyo 2"
,
"trainer":
"id": 1,
"name": "-"
,
"hour": "18",
"day": "2"
,
"0":
"id": 127,
"name": "Zumba",
"quota": 6,
"course_date": "2015-09-02T19:00:00+0000",
"studio":
"id": 1,
"name": "Stüdyo 1"
,
"trainer":
"id": 1,
"name": "-"
,
"hour": "19",
"day": "2"
,
"0":
"id": 148,
"name": "Kick Box",
"quota": 6,
"course_date": "2015-09-02T20:00:00+0000",
"studio":
"id": 1,
"name": "Stüdyo 1"
,
"trainer":
"id": 1,
"name": "-"
,
"hour": "20",
"day": "2"
,
"0":
"id": 138,
"name": "Crunch 30 Min.",
"quota": 8,
"course_date": "2015-09-03T12:15:00+0000",
"studio":
"id": 1,
"name": "Stüdyo 1"
,
"trainer":
"id": 1,
"name": "-"
,
"hour": "12",
"day": "3"
,
"0":
"id": 121,
"name": "Pilates",
"quota": 8,
"course_date": "2015-09-03T19:00:00+0000",
"studio":
"id": 2,
"name": "Stüdyo 2"
,
"trainer":
"id": 1,
"name": "-"
,
"hour": "19",
"day": "3"
,
"0":
"id": 117,
"name": "TRX",
"quota": 8,
"course_date": "2015-09-03T20:00:00+0000",
"studio":
"id": 2,
"name": "Stüdyo 2"
,
"trainer":
"id": 1,
"name": "-"
,
"hour": "20",
"day": "3"
,
"0":
"id": 142,
"name": "Pilates",
"quota": 8,
"course_date": "2015-09-04T12:15:00+0000",
"studio":
"id": 2,
"name": "Stüdyo 2"
,
"trainer":
"id": 1,
"name": "-"
,
"hour": "12",
"day": "4"
,
"0":
"id": 141,
"name": "Crunch 30 Min.",
"quota": 8,
"course_date": "2015-09-04T19:30:00+0000",
"studio":
"id": 2,
"name": "Stüdyo 2"
,
"trainer":
"id": 1,
"name": "-"
,
"hour": "19",
"day": "4"
,
"0":
"id": 130,
"name": "Crunch 30 Min.",
"quota": 8,
"course_date": "2015-09-05T14:00:00+0000",
"studio":
"id": 2,
"name": "Stüdyo 2"
,
"trainer":
"id": 1,
"name": "-"
,
"hour": "14",
"day": "5"
]
我想我现在很接近了。但一定是这样的；
DAY
HOUR
HOUR
DAY
HOUR
HOUR
【问题讨论】：
您可以使用分组方式 我试过按小时和天分组。修复错误后会看到。 你能给我提供一些数据的表架构吗 更新了我的问题。 使用HOUR(c.courseDate) 代替hour 和day 相同
【参考方案1】：
要获得可视化示例表，请使用：
工作日（日期）
返回日期的工作日索引（0 = 星期一，1 = 星期二，... 6 = 周日
select hour(date), -- group by hour
case when weekday(date)=0 then course_name else null end as Monday, -- 1 col for each weekday
.....
case when weekday(date)=6 then course_name else null end as Sunday
from table
where -- select a monday to sunday calendar week unique by year
date(date) - interval weekday(date)=date(curdate()) - interval weekday(curdate())
group by hour(date)
要获得您提到的其他变体：
select right(date, 2), -- day of month,
hour(date) --hour,
course_name
from table
group by 1,2
【讨论】：
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