如何从xml中删除节点？

Posted 2023-04-19

【中文标题】如何从xml中删除节点？

【英文标题】：How to remove node from xml?

【发布时间】：2019-04-12 16:44:44

【问题描述】：

我有xml：

<Info>
    <info_1/>
    <info_2/>
    <info_3>
        <i ID="1"/>
        <i ID="2"/>
        <i ID="3"/>
    </info_3>
    <info_4>
    </indo_4>
</Info>  

我需要删除 info_3 中的特定节点，例如 ID = 1 的节点，我该怎么做？

我尝试这样做，但日志显示在长度 = 3 之前和之后：

DocumentBuilderFactory dbFactory = DocumentBuilderFactory.newInstance();
DocumentBuilder dBuilder = dbFactory.newDocumentBuilder();
Document doc = dBuilder.parse(new InputSource(new StringReader(bb)));
doc.getDocumentElement().normalize();  

NodeList nList = doc.getElementsByTagName("i");  
Log.e("LOG", "nList.getLength() = " + nList.getLength());
Node node=nList.item(1);  
node.getParentNode().removeChild(node);  
Log.e("LOG", "nList.getLength() = " + nList.getLength());

【参考方案1】：

对我有帮助的解决方案：

DocumentBuilderFactory dbFactory = DocumentBuilderFactory.newInstance();
DocumentBuilder dBuilder = dbFactory.newDocumentBuilder();
Document doc = dBuilder.parse(new InputSource(new StringReader(bb)));
doc.getDocumentElement().normalize();  

NodeList nList = doc.getElementsByTagName("i");  
Log.e("LOG", "nList.getLength() = " + nList.getLength());
Set<Element> targetElements = new HashSet<>();
for (int i = 0; i < nList_Loan_guarantor.getLength(); i++) 
  Element e = (Element)nList_Loan_guarantor.item(i);
  if ("10938".equals(e.getAttribute("ID"))) 
  targetElements.add(e);
  


for (Element e: targetElements) 
   e.getParentNode().removeChild(e);
   

doc.getDocumentElement().normalize();
NodeList nList_2 = doc.getElementsByTagName("i"); 
Log.e("LOG", "nList.getLength() = " + nList.getLength());