如何导入特定联系人的电话号码？

Posted 2023-04-15

【中文标题】如何导入特定联系人的电话号码？

【英文标题】：How to import a Specific Contact's phone number?

【发布时间】：2018-04-26 12:36:47

【问题描述】：

我正在尝试读取使用联系人选择器选择的联系人的电话号码。 显示名称工作正常，但电话号码没有。 代码：

//calling Contact Picker
public void CPick(View v)
        Intent intent=new Intent(Intent.ACTION_PICK, ContactsContract.Contacts.CONTENT_URI);
        startActivityForResult(intent, PICK_CONTACT);
    
    @Override
//Contact Picker here:
    protected void onActivityResult(int reqCode, int resultCode, Intent data)
        super.onActivityResult(reqCode,resultCode, data);

        if (reqCode==PICK_CONTACT)
            if(resultCode==AppCompatActivity.RESULT_OK)
                Uri contatctData=data.getData();
                Cursor c=getContentResolver().query(contatctData,null,null,null,null);
                if (c.moveToFirst())
                    //String name=c.getString(c.getColumnIndexOrThrow(ContactsContract.Contacts.DISPLAY_NAME));
//Above line works Fine

                    String name=c.getString(c.getColumnIndexOrThrow(ContactsContract.CommonDataKinds.Phone.NUMBER));
//Above line gives error on runtime "invalid column"
                    Toast.makeText(this,"U have picked:"+name,Toast.LENGTH_SHORT).show();



                
            

        
    

非常感谢任何帮助，因为我在任何地方都找不到相关答案。

【参考方案1】：

如果您想让用户选择电话号码，最好的选择是使用PHONE-PICKER 而不是CONTACT-PICKER：

Intent intent = new Intent(Intent.ACTION_PICK, CommonDataKinds.Phone.CONTENT_URI);
startActivityForResult(intent, PICK_PHONE);

...

protected void onActivityResult(int requestCode, int resultCode, Intent intent)
    if (requestCode == PICK_PHONE && resultCode == RESULT_OK)
        Uri phoneUri = intent.getData();
        Cursor cur = getContentResolver().query(phoneUri, new String[]  Phone.DISPLAY_NAME, Phone.NUMBER , null, null, null);
        if (cur != null && cur.moveToFirst())
            String name = cur.getString(0);
            String number = cur.getString(1);
            Log.d("PHONE-PICKER", "User picker: " + name + " - " + number);
            cur.close();
        
    

【讨论】：

没有什么叫做 PICK_PHONE

像魅力一样工作。你又救了我一天:)

【参考方案2】：

试试这个方法：

private void retrieveContactNumber() 

  String contactNumber = null;

  // getting contacts ID
  Cursor cursorID = getContentResolver().query(uriContact,
        new String[]ContactsContract.Contacts._ID,
        null, null, null);

  if (cursorID.moveToFirst()) 

    contactId = cursorID.getString(cursorID.getColumnIndex(ContactsContract.Contacts._ID));
  

  cursorID.close();

  Log.d(TAG, "Contact ID: " + contactId);

  // Using the contact ID now we will get contact phone number
  Cursor cursorPhone = getContentResolver().query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI,
        new String[]ContactsContract.CommonDataKinds.Phone.NUMBER,

        ContactsContract.CommonDataKinds.Phone.CONTACT_ID + " = ? AND " +
                ContactsContract.CommonDataKinds.Phone.TYPE + " = " +
                ContactsContract.CommonDataKinds.Phone.TYPE_MOBILE,

        new String[]contactId, null);

  if (cursorPhone.moveToFirst()) 
    contactNumber = cursorPhone.getString(cursorPhone.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER));
  

  cursorPhone.close();

  Log.d(TAG, "Contact Phone Number: " + contactNumber);

您应该会在 logcat 中看到联系电话。

【讨论】：

不返回我选择的联系人的电话号码，它总是选择 ID==1 的联系人。与电话号码相同。