如何使用联系人 ID 获取特定的联系电话

Posted 2023-04-15

【中文标题】如何使用联系人 ID 获取特定的联系电话

【英文标题】：How to get Specific Contact Number by using Contact Id

【发布时间】：2012-03-27 12:46:38

【问题描述】：

这里我的联系人姓名显示在列表视图中。通过单击列表，我得到ContactName 和Contact Id。从那我想通过使用Contact ID或Contact name来获取Phone number，请帮助我。

这是我的代码

void ReadContacts(String sort) 
    final Uri uri = ContactsContract.Contacts.CONTENT_URI;
    final String[] projection = new String[] 
            ContactsContract.Contacts._ID,
            ContactsContract.Contacts.DISPLAY_NAME
    ;
    //boolean mShowInvisible = false;
    String selection = ContactsContract.Contacts.IN_VISIBLE_GROUP + " = '1'";
    String[] selectionArgs = null;
    final String sortOrder = ContactsContract.Contacts.DISPLAY_NAME + " COLLATE LOCALIZED ASC";

    m_curContacts = managedQuery(uri, projection, selection, selectionArgs, sortOrder);
    String[] fields = new String[] ContactsContract.Data.DISPLAY_NAME;
    m_slvAdapter = new SimpleCursorAdapter(this, 
                android.R.layout.simple_list_item_1, 
                m_curContacts,
                fields, 
                new int[] android.R.id.text1);
    m_slvAdapter.setFilterQueryProvider(new FilterQueryProvider() 

        public Cursor runQuery(CharSequence constraint) 
            Log.d(LOG_TAG, "runQuery constraint:"+constraint);
            String selection = ContactsContract.Contacts.IN_VISIBLE_GROUP + " = '1'" +
                    " AND "+ ContactsContract.Contacts.DISPLAY_NAME + " LIKE '%"+constraint+"%'";
            String[] selectionArgs = null;//new String[]"'1'";//, ;
            Cursor cur = managedQuery(uri, projection, selection, selectionArgs, sortOrder);
            return cur;
        

   );
   m_lvContacts.setAdapter(m_slvAdapter); 
   //  cur.close();





public void onItemClick(AdapterView<?> arg0, View v, int position, long id) 
    ContentResolver cr;
    Cursor cursor = (Cursor) m_lvContacts.getItemAtPosition(position);
    String szDisplayName = cursor.getString(cursor.getColumnIndexOrThrow( ContactsContract.Contacts.DISPLAY_NAME));
    String szId = cursor.getString(cursor.getColumnIndexOrThrow( ContactsContract.Contacts._ID));
    int nId = cursor.getInt(cursor.getColumnIndexOrThrow( ContactsContract.Contacts._ID));
    Log.d(LOG_TAG, "Item click:"+position+" szId:"+szId+" nId:"+nId+" Data:"+szDisplayName);
    Toast.makeText(getBaseContext(), "Item click:"+phoneNumber+" szId:"+szId+" nId:"+nId+" Data:"+szDisplayName, Toast.LENGTH_SHORT).show();

【问题讨论】：

看这里***.com/questions/3370628/…

我使用了上面的链接，但 phoneindex 产生了价值

***.com/questions/3044545/… 尝试在SO上搜索。这样的问题已经问过了，你只需安排一下

【参考方案1】：

试试这个

ArrayList<String> phones = new ArrayList<String>();

Cursor cursor = mContentResolver.query(
        CommonDataKinds.Phone.CONTENT_URI, 
        null, 
        CommonDataKinds.Phone.CONTACT_ID +" = ?", 
        new String[]id, null);

while (cursor.moveToNext()) 

    phones.add(cursor.getString(cursor.getColumnIndex(CommonDataKinds.Phone.NUMBER)));
 

cursor.close();
return(phones);

【讨论】：

我不想要电话号码列表，我需要一个特定号码

你检查了吗？我认为它只返回一个数字

【参考方案2】：

试试这个

public void getNameUsingContactId(String contactId)

    String cContactIdString = ContactsContract.Contacts._ID;
    Uri cCONTACT_CONTENT_URI = ContactsContract.Contacts.CONTENT_URI;
    String cDisplayNameColumn = ContactsContract.Contacts.DISPLAY_NAME;

    String selection = cContactIdString + " = ? ";
    String[] selectionArgs = new String[]String.valueOf(contactId);

    Cursor cursor = mContext.getContentResolver().query(cCONTACT_CONTENT_URI, null, selection, selectionArgs, null);
    if ((cursor != null) && (cursor.getCount() > 0)) 
        cursor.moveToFirst();
        while ((cursor != null) && (cursor.isAfterLast() == false)) 
            if (cursor.getColumnIndex(cContactIdString) >= 0) 
                if (contactId.equals(cursor.getString(cursor.getColumnIndex(cContactIdString)))) 
                    String name = cursor.getString(cursor.getColumnIndex(cDisplayNameColumn));
                     break;
                
            
            cursor.moveToNext();
        
    
    if (cursor != null)
        cursor.close();  
   

【参考方案3】：

您会在数据表中找到电话号码。在rawcontacts表中找到对应的rawcontact id（使用contact ID作为where条件），使用这些raw contact id查询数据表。电话号码将具有特定的 mime 类型（现在远离文档），因此您可以识别它们。 希望这会有所帮助！

提示：从您的模拟器/设备复制contacts2.db 数据库并使用Squirrel（SQLite jdbc 驱动程序）在联系人数据库中四处寻找。 db 位于 /data/data/ 在列表中查找联系人）。

【参考方案4】：

各位，我得到了答案：

如果您需要，请使用此代码：

  Cursor cursor = (Cursor) m_lvContacts.getItemAtPosition(position);
        String szDisplayName = cursor.getString(cursor.getColumnIndexOrThrow( ContactsContract.Contacts.DISPLAY_NAME));
        String szId = cursor.getString(cursor.getColumnIndexOrThrow( ContactsContract.Contacts._ID));
        int nId = cursor.getInt(cursor.getColumnIndexOrThrow( ContactsContract.Contacts._ID));
         long l = Long.parseLong(szId);
        int type=ContactsContract.CommonDataKinds.Phone.TYPE_MOBILE;




 cursor = getContentResolver().query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI,
         null,
         ContactsContract.CommonDataKinds.Phone.CONTACT_ID+"='"+szId+"'",
         null, null);

            int phoneNumberIndex = cursor
                    .getColumnIndexOrThrow(ContactsContract.CommonDataKinds.Phone.NUMBER);

            Log.d(TAG, String.valueOf(cursor.getCount()));

            if (cursor != null) 
                Log.v(TAG, "Cursor Not null");
                try 
                    if (cursor.moveToNext()) 
                        Log.v(TAG, "Moved to first");
                        Log.v(TAG, "Cursor Moved to first and checking");
                        phoneNumber = cursor.getString(phoneNumberIndex);
                        System.out.println("HAGSd"+phoneNumber);
                    
                 finally 
                    Log.v(TAG, "In finally");
                    cursor.close();
                

【参考方案5】：

public static final String contactIdByPhoneNumber(Context ctx, String phoneNumber) 
    String contactId = null;
    if (phoneNumber != null && phoneNumber.length() > 0) 
        ContentResolver contentResolver = ctx.getContentResolver();

        Uri uri = Uri.withAppendedPath(ContactsContract.PhoneLookup.CONTENT_FILTER_URI, Uri.encode(phoneNumber));

        String[] projection = new String[]  PhoneLookup._ID ;

        Cursor cursor = contentResolver.query(uri, projection, null, null, null);

        if (cursor != null) 
            while (cursor.moveToNext()) 
                contactId = cursor.getString(cursor.getColumnIndexOrThrow(PhoneLookup._ID));
            
            cursor.close();
        
    
    return contactId;