在iOS中的字典中使用字典数组的NSPredicate进行过滤
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【中文标题】在iOS中的字典中使用字典数组的NSPredicate进行过滤【英文标题】:Filter using NSPredicate of Array of Dictionary within dictionary in iOS 【发布时间】:2018-03-28 19:02:57 【问题描述】:Rewards -- Array
Normal Reward -- Object
Offer -- Dictionary
Meta -- Dictionary
rewardId -- String
Normal Reward -- Object
Offer -- Dictionary
Meta -- Dictionary
rewardId -- String
我有上面的层次结构,我必须匹配一个特定的 rewardId 以获得一个值。如何使用 NSPredicate 实现这一点。
【问题讨论】:
[NSPredicate predicateWithFormat:@"SELF.nameOfOfferProperty.nameOfMetaKey.rewardId == %@", myRewardIdToMatch]
?
【参考方案1】:
这个谓词应该可以解决问题:
NSPredicate *predicate = [NSPredicate predicateWithFormat:@"SELF.nameOfOfferProperty.nameOfMetaKey.nameOfRewardIdKey == %@", myRewardIdToMatch]
我根据您的需要明确命名了要走的路径。
使用示例代码(这样您就可以看到需要时使用的名称):
NSMutableArray *rewards = [[NSMutableArray alloc] init];
for (NSUInteger i = 0; i < 10; i ++)
NSString *rewardId = [NSString stringWithFormat:@"rewardID %@", (i%2 == 0)?@"Target":@"NonWanted"];
NSString *otherMetaValue = [NSString stringWithFormat:@"otherMetaValue-%ld", i];
NSString *otherOfferValue = [NSString stringWithFormat:@"otherOfferValue-%ld", i];
NSDictionary *anOfferDict = @@"meta": @@"rewardId": rewardId,
@"otherMetaKey": otherMetaValue,
@"otherOfferKey": otherOfferValue;
Reward *aReward = [[Reward alloc] initWithOfferDict:anOfferDict andIntValue:i];
[rewards addObject:aReward];
NSLog(@"Rewards: %@", rewards);
NSString * myRewardIdToMatch = @"rewardID Target";
NSPredicate *predicate = [NSPredicate predicateWithFormat:@"SELF.offer.meta.rewardId == %@", myRewardIdToMatch];
NSArray *filteredRewards = [rewards filteredArrayUsingPredicate:predicate];
NSLog(@"FilteredRewards: %@", filteredRewards);
还有
@implementation Reward
-(id)initWithOfferDict:(NSDictionary *)dict andIntValue:(NSUInteger)intV
self = [super init];
if (self)
_offer = dict;
_intV = intV;
return self;
覆盖 description
可能会有所帮助,并说明它是否有效:
-(NSString *)description
return [NSString stringWithFormat:@"<%@ %p> with IntValue: %ld and rewardID:\n%@", [self class], self, _intV, _offer[@"meta"][@"rewardId"]];
@end
输出:
$> Rewards: (
"<Reward 0x60000022ce80> with IntValue: 0 and rewardID: rewardID Target",
"<Reward 0x60000022ce00> with IntValue: 1 and rewardID: rewardID NonWanted",
"<Reward 0x60000022cf80> with IntValue: 2 and rewardID: rewardID Target",
"<Reward 0x60000022cea0> with IntValue: 3 and rewardID: rewardID NonWanted",
"<Reward 0x60000022cf20> with IntValue: 4 and rewardID: rewardID Target",
"<Reward 0x60000022ce40> with IntValue: 5 and rewardID: rewardID NonWanted",
"<Reward 0x60000022cfa0> with IntValue: 6 and rewardID: rewardID Target",
"<Reward 0x60000022cfc0> with IntValue: 7 and rewardID: rewardID NonWanted",
"<Reward 0x60000022ce60> with IntValue: 8 and rewardID: rewardID Target",
"<Reward 0x60000022cec0> with IntValue: 9 and rewardID: rewardID NonWanted"
)
$> FilteredRewards: (
"<Reward 0x60000022ce80> with IntValue: 0 and rewardID: rewardID Target",
"<Reward 0x60000022cf80> with IntValue: 2 and rewardID: rewardID Target",
"<Reward 0x60000022cf20> with IntValue: 4 and rewardID: rewardID Target",
"<Reward 0x60000022cfa0> with IntValue: 6 and rewardID: rewardID Target",
"<Reward 0x60000022ce60> with IntValue: 8 and rewardID: rewardID Target"
)
【讨论】:
您介意说出原因吗?有没有崩溃?那么崩溃日志呢?你用了什么?你的物品看起来像我的吗?不同的?你尝试了什么?你可以看到我的代码在运行,那么我的和你的有什么不同呢?以上是关于在iOS中的字典中使用字典数组的NSPredicate进行过滤的主要内容,如果未能解决你的问题,请参考以下文章