Flutter 中的 Dart Futures 问题:断言失败:第 146 行:'<optimized out>': is not true

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【中文标题】Flutter 中的 Dart Futures 问题:断言失败:第 146 行:\'<optimized out>\': is not true【英文标题】:Trouble with Dart Futures in Flutter : Failed assertion: line 146: '<optimized out>': is not trueFlutter 中的 Dart Futures 问题:断言失败:第 146 行:'<optimized out>': is not true 【发布时间】:2019-04-11 14:17:37 【问题描述】:

我正在为我的应用程序构建一个用户身份验证模块,但我遇到了一些异步代码的问题。

首先,这是抛出的错误:

E/flutter (17162): [ERROR:flutter/shell/common/shell.cc(188)] Dart 错误:未处理的异常: E/flutter(17162):“dart:async/future_impl.dart”:断言失败:第 146 行:“优化”:不正确。 E/flutter (17162): #0 _AssertionError._doThrowNew (dart:core/runtime/liberrors_patch.dart:40:39) E/flutter (17162): #1 _AssertionError._throwNew (dart:core/runtime/liberrors_patch.dart:36:5) E/flutter (17162): #2 _FutureListener.handleError (dart:async/future_impl.dart:146:14) E/flutter (17162): #3 Future._propagateToListeners.handleError (dart:async/future_impl.dart:654:47) E/flutter (17162): #4 Future._propagateToListeners (dart:async/future_impl.dart:675:24) E/flutter (17162): #5 Future._completeError (dart:async/future_impl.dart:494:5) E/flutter (17162): #6 _SyncCompleter._completeError (dart:async/future_impl.dart:55:12) E/flutter (17162): #7 _Completer.completeError (dart:async/future_impl.dart:27:5) E/flutter (17162): #8 _AsyncAwaitCompleter.completeError (dart:async/runtime/libasync_patch.dart:40:18) E/flutter (17162):#9 FirebaseAuth.signInWithEmailAndPassword(包:firebase_auth/firebase_auth.dart) E/颤振(17162): E/flutter (17162):#10 Session.login。 (包:mood_map/utilities/session.dart:31:24) E/flutter (17162): #11 _RootZone.runUnary (dart:async/zone.dart:1379:54) E/flutter (17162): #12 _FutureListener.handleValue (dart:async/future_impl.dart:129:18) E/flutter (17162): #13 Future._propagateToListeners.handleValueCallback (dart:async/future_impl.dart:642:45) E/flutter (17162): #14 Future._propagateToListeners (dart:async/future_impl.dart:671:32) E/flutter (17162): #15 Future._complete (dart:async/future_impl.dart:476:7) E/flutter (17162): #16 _SyncCompleter.complete (dart:async/future_impl.dart:51:12) E/flutter (17162): #17 _AsyncAwaitCompleter.complete (dart:async/runtime/libasync_patch.dart:28:18) E/flutter (17162): #18 _completeOnAsyncReturn (dart:async/runtime/libasync_patch.dart:295:13) E/flutter (17162): #19 Session._checkUserAlreadyExists (package:mood_map/utilities/session.dart) E/颤振(17162): E/flutter (17162): #20 Session.login (package:mood_map/utilities/session.dart:27:11)

这里是涉及的功能:

static final FirebaseAuth _authenticator = FirebaseAuth.instance;

static void login(BuildContext context, String email, String password) async 

email = email.trim();
password = password.trim();

//Check if the user already exists
await _checkUserAlreadyExists(email).then((exists) 

  if(exists) 

    _authenticator.signInWithEmailAndPassword(email: email, password: password)
        .then((FirebaseUser user)  _loginSuccess(); )
        .catchError((Error e)  _loginFailure(context); );

   else 

    Utilities.showMessageDialog(context, "That user doesn't exist. Please create an account below.");

  

);

 

----------------------------------------------------------------------

static Future createUserAccount(BuildContext context, email, String password) async 

//Check if the user already exists
await _checkUserAlreadyExists(email).then((exists) 

  if(exists) 

    Utilities.showMessageDialog(context, "That user already exists. Please login or select another account.");
    AppNavigator.navigateToLoginScreen();

   else 

    _authenticator.createUserWithEmailAndPassword(email: email, password: password)
        .then((FirebaseUser user)  _createUserSuccess(); )
        .catchError((Error e)  _createUserFailure(context); );

  

);


简而言之,对 _authenticator.signonWithEmailAndPassword() 的调用失败。我知道 _authenticator 实例正在使用其他函数,所以我知道这不是 Firebase 本身的问题。

我担心我从另一个异步函数 _checkIfUserAlreadyExists() 中调用另一个异步函数 _authenticator.signonWithEmailAndPassword() 做错了事。从我读过的内容来看,这似乎可以在 .then() 块中执行,但错误消息似乎非常坚持认为这与函数调用的异步性质的设置有关。

想法?

【问题讨论】:

上述问题你得到解决方案了吗? 没有。我做了更多的研究,这似乎是当前版本的 Flutter 的系统性问题。我发现了一个报告它的 github 问题,以便开发人员知道。我也发布了我的发现。见:github.com/flutter/flutter/issues/23512 【参考方案1】:

如果您使用.then() 子句,请不要使用await

.then()await 是处理Future 的两种不同方式,但不应用于相同的Future 实例。

【讨论】:

【参考方案2】:

考虑使用 async - await 来捕获“最后一步”中的错误。这个回答https://github.com/flutter/flutter/issues/22734对我帮助很大。

以下是我从一个我不记得的来源获得的代码 sn-p,但它帮助我了解了如何正确使用 Futures。我对其进行了一些修改以测试我的确切情况(添加了 ma​​in4()divideFullAsyncNested() 函数)。希望对你有帮助。

// SO 29378453
import 'dart:async';

import 'package:login_app/constants.dart';

main() 
  // fails
  main1();
  main2();
  main3();
  main4();


Future<double> divide(int a, b) 
  // this part is still sync
  if (b == 0) 
    throw new Exception('Division by zero divide non-async');
  
  // here starts the async part
  return new Future.value(a / b);


Future<double> divideFullAsync(int a, b) 
  return new Future(() 
    if (b == 0) 
      throw new Exception('Division by zero full async');
    
    return new Future.value(a / b);
    // or just
    // return a / b;
  );


Future<double> divideFullAsyncNested() 
  return divideFullAsync(7, 8).then(
    (val) 
      return divideFullAsync(5, 0).then(
        (val2) 
          return Future(() 
            if (val2 == 1) 
              throw Exception('Innermost: Result not accepted exception.');
            
            return val2;
          );
        ,
      ).catchError((err) => throw Exception('Inner:    $err'));
    ,
  ).catchError((err) => throw Exception('Outter: $err'));


//Future<double> divideFullAsyncNested() 
//  return divideFullAsync(9, 9).then(
//    (val) 
//      return Future(
//        () 
//          if (val == 1) 
//            throw Exception('Result not accepted exception.');
//          
//          return val;
//        ,
//      );
//    ,
//  ).catchError((err) => throw Exception(err.toString()));
//

// async error handling doesn't catch sync exceptions

void main1() async 
  try 
//    divide(1, 0).then((result) => print('(1) 1 / 0 = $result')).catchError(
//        (error) => print('(1)Error occured during division: $error'));
    var result = await divide(1, 0);
    print('(1) 1 / 0 = $result');
   catch (ex) 
    print('(1.1)Error occured during division: $ex.toString()');
  


// async error handling catches async exceptions
void main2() 
  divideFullAsync(1, 0)
      .then((result) => print('(2) 1 / 0 = $result'))
      .catchError(
          (error) => print('(2) Error occured during division: $error'));


// async/await allows to use try/catch for async exceptions
main3() async 
  try 
    await divideFullAsync(1, 0);
    print('3');
   catch (error) 
    print('(3) Error occured during division: $error');
  


main4() async 
//  try 
//    await divideFullAsyncNested();
//   on Exception catch (e) 
//    print("(4) $e.toString().replaceAll('Exception:', '').trimLeft().trimRight()");
//  
  try 
    divideFullAsyncNested()
        .then((v) => print(v))
        .catchError((err) => print(Constants.refinedExceptionMessage(err)));
   on Exception catch (e) 
    print("(4) $Constants.refinedExceptionMessage(e)");
  

【讨论】:

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