foreach中的php foreach
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【中文标题】foreach中的php foreach【英文标题】:php foreach within foreach 【发布时间】:2012-01-27 12:28:40 【问题描述】:我想要实现的是能够像这样打印结果:
Header 1
Link 1
Link 2
Header 2
Link 3
Header 3
Link 4
Link 5
但是下面的代码打印的结果是这样的:
Header 1
Link 1
Link 2
Header 2
Link 1
Link 2
Link 3
Header 3
Link 1
Link 2
Link 3
Link 4
Link 5
使用php pdo wrapper class,据我所知,我别无选择,只能使用“foreach”而不是“while”来循环结果,这是我的代码:
$bind = array(":users_id" => $id);
$categoryQry = $db->select("category","users_id=:users_id", $bind);
//loop Headers
foreach($categoryQry AS $CatRes)
$category_name = $CatRes['category_name'];
$bind = array(
":users_id" => $id,
":link_category" => $CatRes['category_id']
);
$linkQry = $db->select("links", "users_id=:users_id AND link_category=:link_category", $bind);
//loop Links under each header
foreach($linkQry AS $LinkRes)
$link_url = $LinkRes['link_url'];
//$link_row outputs the links under each header, this is where the problem is
$link_row .= DisplayLayout("link_row.html","\$link_url");
//$header outputs the result OK (3 headers as stated in above example)
$header .= DisplayLayout("header.html","\$category_name,\$link_row");
//note that DisplayLayout is my template function which is used for outputting variables using an HTML file.
我一直在尝试其他几种方法,但都没有成功,希望有人能在我的代码中发现问题并引导我走向正确的方向。
提前谢谢你,圣诞快乐。
【问题讨论】:
$link_row 只被添加到,你需要在每个外循环之后清空它 【参考方案1】:您需要在此行之前重置 $link_row:foreach($linkQry AS $LinkRes)
【讨论】:
这是我忽略的逻辑方面。感谢您的指点,解决了我的问题。【参考方案2】:$bind = array(":users_id" => $id);
$categoryQry = $db->select("category","users_id=:users_id", $bind);
//loop Headers
foreach($categoryQry AS $CatRes)
$category_name = $CatRes['category_name'];
$bind = array(
":users_id" => $id,
":link_category" => $CatRes['category_id']
);
$linkQry = $db->select("links", "users_id=:users_id AND link_category=:link_category", $bind);
//loop Links under each header
$link_row='';
foreach($linkQry AS $LinkRes)
$link_url = $LinkRes['link_url'];
//$link_row outputs the links under each header, this is where the problem is
$link_row .= DisplayLayout("link_row.html","\$link_url");
//$header outputs the result OK (3 headers as stated in above example)
$header .= DisplayLayout("header.html","\$category_name,\$link_row");
//note that DisplayLayout is my template function which is used for outputting variables using an HTML file.
【讨论】:
【参考方案3】://reset linkrow
$link_row = '';
foreach($linkQry AS $LinkRes)
$link_url = $LinkRes['link_url'];
//$link_row outputs the links under each header, this is where the problem is
$link_row .= DisplayLayout("link_row.html","\$link_url");
【讨论】:
【参考方案4】:在第二个循环之前为空 $link_row
。
【讨论】:
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