如何快速按下按钮在 Xcode 上生成声音？

Posted 2023-02-25

【中文标题】如何快速按下按钮在 Xcode 上生成声音？

【英文标题】：How to rapidly press a button to generate sound on Xcode?

【发布时间】：2017-06-07 02:51:39

【问题描述】：

这是我的以下 Xcode 项目代码。当我按下“play()”时，会发出短促的鼓声。问题是，当我连续多次点击自定义视图时，我希望连续出现快速的鼓声。但是，声音会在完整剪辑（2 秒）完成后出现，留下大量死区。我尝试了很多不同的方法，但我做不到。

@IBOutlet weak var tabla: TablaHead!

var tablaSoundUrl = NSURL(fileURLWithPath: Bundle.main.path(forResource: "TablaSound", ofType: "mp3")!)
var tablaAudioPlayer = AVAudioPlayer()


override func viewDidLoad() 
    super.viewDidLoad()
    tablaAudioPlayer = try! AVAudioPlayer(contentsOf: tablaSoundUrl as URL)


@IBAction func tapped(_ sender: UITapGestureRecognizer) 
    if sender.state == .ended 
        playNoise()
    


public func playNoise() 
    if (tablaAudioPlayer.isPlaying) 
        tablaAudioPlayer.stop()
        tablaAudioPlayer.play()
     else 
        tablaAudioPlayer.play()
    

【参考方案1】：

试试这样的

@IBOutlet weak var tabla: TablaHead!

var tablaSoundUrl = NSURL(fileURLWithPath: Bundle.main.path(forResource: "TablaSound", ofType: "mp3")!)
var tablaAudioPlayer = AVAudioPlayer()
var tapsCount = 0

override func viewDidLoad() 
    super.viewDidLoad()
    tablaAudioPlayer = try! AVAudioPlayer(contentsOf: tablaSoundUrl as URL)


@IBAction func tapped(_ sender: UITapGestureRecognizer) 
    tapsCount += 1
    if sender.state == .ended && tapsCount == 1 
        playNoise()
    


public func playNoise() 
    tapsCount -= 1
    tablaAudioPlayer.play()
    if tapsCount > 0 
        playNoise()
    

【讨论】：

不走运。我认为问题在于我不完全了解 AVAudioPlayer。感谢您的尝试！