SKAction.moveToX 重复值变化

Posted 2023-03-16

【中文标题】SKAction.moveToX 重复值变化

【英文标题】：SKAction.moveToX repeat with value change

【发布时间】：2016-06-29 02:54:40

【问题描述】：

我希望能够在每移动 20 个像素时暂停移动球我尝试了这个但什么也没做，球停留在它开始的点它不会移动到屏幕的末端，我知道我没有放 waitForDuration ，因为我想检查它是否会移动

func spwan()

    let ball:SKSpriteNode = SKScene(fileNamed: "Ball")?.childNodeWithName("ball") as! SKSpriteNode
    ball.removeFromParent()
    self.addChild(ball)
    ball.name = "spriteToTrack"
    ball.zPosition = 0
    ball.position = CGPointMake(1950, 1000)
    var num:CGFloat = ball.position.x
    let a1 = SKAction.moveToX(num - 20, duration: 10)
    // i want to get to -50 let a1 = SKAction.moveToX(-50 , duration: 10)       
    let minus = SKAction.runBlock
        num -= 20
    
    let sq1 = SKAction.sequence([a1,minus])
    ball.runAction(SKAction.repeatAction(sq1, count: 10)      

【问题讨论】：

很好，我看到您刚刚收到了很好的答复。祝你好运

【参考方案1】：

在上面的代码中，球至少应该移动 20 像素，但 10 秒内移动 20 像素可能看起来像是静止的。无论如何，我认为您使用moveToX 而不是moveBy: 使事情变得过于复杂了，所以（稍微调整一下）你可能会更好地使用这样的东西：

func spawn() 
    let x: CGFloat = 1950
    let xDelta: CGFloat = -20
    let xDestination: CGFloat = -50
    let repeats = Int((x - xDestination)/fabs(xDelta))

    let move = SKAction.moveBy(CGVectorMake(xDelta, 0), duration: 2) // made it a lot quicker to show that stuff is happening
    move.timingMode = .EaseInEaseOut

    let ball:SKSpriteNode = SKScene(fileNamed: "Ball")?.childNodeWithName("ball") as! SKSpriteNode
    ball.removeFromParent()
    ball.name = "spriteToTrack"

    ball.position = CGPointMake(x, 1000)

    addChild(ball)
    ball.runAction(SKAction.repeatAction(move, count: repeats))