使用多个选择作为列优化查询
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【中文标题】使用多个选择作为列优化查询【英文标题】:Optimising query with multiple selects as columns 【发布时间】:2020-10-30 05:40:32 【问题描述】:我有一个查询:
SELECT DISTINCT player_1 AS player,
(SELECT COUNT(*) FROM results WHERE player_1=player OR player_2=player) AS since_start_matches,
(SELECT COUNT(*) FROM results WHERE (player_1=player OR player_2=player) AND ht_total_goals=0) AS since_start_ht_0,
(SELECT COUNT(*) FROM results WHERE (player_1=player OR player_2=player) AND ht_total_goals=1) AS since_start_ht_1,
(SELECT COUNT(*) FROM results WHERE (player_1=player OR player_2=player) AND ht_total_goals=2) AS since_start_ht_2,
(SELECT COUNT(*) FROM results WHERE (player_1=player OR player_2=player) AND ht_total_goals=3) AS since_start_ht_3,
(SELECT COUNT(*) FROM results WHERE (player_1=player OR player_2=player) AND ht_total_goals=4) AS since_start_ht_4,
(SELECT COUNT(*) FROM results WHERE (player_1=player OR player_2=player) AND ht_total_goals>=5) AS since_start_ht_5_plus
FROM results ORDER BY player
results
表有 25000 个条目,执行此查询大约需要 7 秒,这太长了。该查询效率极低,因为我创建的每一列都在同一个表上再次搜索,但条件不同。
我尝试在 where 子句中索引感兴趣的列。这会关闭几秒钟。但是还是太慢了。
处理此类查询的最佳方法是什么?
我正在使用 MariaDB 10.2
【问题讨论】:
也就是说,最好的方法可能是处理应用程序代码中数据显示的所有问题 【参考方案1】:取消透视数据然后聚合:
SELECT player,
COUNT(*) AS since_start_matches,
SUM(ht_total_goals=0) AS since_start_ht_0,
SUM(ht_total_goals=1) AS since_start_ht_1,
SUM(ht_total_goals=2) AS since_start_ht_2,
SUM(ht_total_goals=3) AS since_start_ht_3,
SUM(ht_total_goals=4) AS since_start_ht_4,
SUM( ht_total_goals>=5) AS since_start_ht_5_plus
FROM ((SELECT player_1 as player, ht_total_goals
FROM results
) UNION ALL
(SELECT player_2 as player, ht_total_goals
FROM results
)
) p
GROUP BY player
【讨论】:
【参考方案2】:您可以使用LEFT JOIN
和conditional aggregation
,如下所示:
SELECT player_1 AS player,
COUNT(T2.player_1) AS since_start_matches,
SUM(CASE WHEN T2.ht_total_goals=0 THEN 1 END) AS since_start_ht_0,
SUM(CASE WHEN T2.ht_total_goals=1 THEN 1 END) AS since_start_ht_1,
SUM(CASE WHEN T2.ht_total_goals=2 THEN 1 END) AS since_start_ht_2,
SUM(CASE WHEN T2.ht_total_goals=3 THEN 1 END) AS since_start_ht_3,
SUM(CASE WHEN T2.ht_total_goals=4 THEN 1 END) AS since_start_ht_4,
SUM(CASE WHEN T2.ht_total_goals>=5 THEN 1 END) AS since_start_ht_5_PLUS
FROM results T1 LEFT JOIN results T2
ON (T2.player_1=T.player OR T2.player_2=T.player)
GROUP BY T1.PLA
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【讨论】:
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