cf965d Single-use Stones

Posted 2020-11-02 poorpool

ref

#include <iostream>
#include <cstdio>
using namespace std;
int a[100005], n, l, ans=0x3f3f3f3f;
int main(){
	cin>>n>>l;
	for(int i=1; i<n; i++){
		scanf("%d", &a[i]);
		a[i] += a[i-1];
	}
	for(int i=l; i<n; i++)
		ans = min(ans, a[i]-a[i-l]);
	cout<<ans<<endl;
	return 0;
}