1060. Are They Equal (25)
Posted 王清河
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If a machine can save only 3 significant digits, the float numbers 12300 and 12358.9 are considered equal since they are both saved as 0.123*105 with simple chopping. Now given the number of significant digits on a machine and two float numbers, you are supposed to tell if they are treated equal in that machine.
Input Specification:
Each input file contains one test case which gives three numbers N, A and B, where N (<100) is the number of significant digits, and A and B are the two float numbers to be compared. Each float number is non-negative, no greater than 10100, and that its total digit number is less than 100.
Output Specification:
For each test case, print in a line "YES" if the two numbers are treated equal, and then the number in the standard form "0.d1...dN*10^k" (d1>0 unless the number is 0); or "NO" if they are not treated equal, and then the two numbers in their standard form. All the terms must be separated by a space, with no extra space at the end of a line.
Note: Simple chopping is assumed without rounding.
Sample Input 1:
3 12300 12358.9
Sample Output 1:
YES 0.123*10^5
Sample Input 2:
3 120 128
Sample Output 2:
NO 0.120*10^3 0.128*10^3
#include<iostream> #include<string> using namespace std; int n; string deal(string s, int &e){ int k = 0; while(s.length() > 0 && s[0] == ‘0‘){ s.erase(s.begin()); } if(s[0] == ‘.‘){ s.erase(s.begin()); while(s.length() > 0 && s[0] == ‘0‘){ s.erase(s.begin()); e--; } }else{ while(k < s.length() && s[k] != ‘.‘){ k++; e++; } if(k < s.length()){ s.erase(s.begin()+k); } } if(s.length() == 0) e = 0; int num = 0;; k = 0; string res; while(num < n){ if(k < s.length()) res += s[k++]; else res +=‘0‘; num++; } return res; } int main(){ string s1,s2,s3,s4; int e1=0,e2=0; cin >> n >> s1 >> s2; s3 = deal(s1,e1); s4 = deal(s2,e2); if(s3 == s4 && e1 == e2){ cout <<"YES 0."<<s3 <<"*10^"<<e1<<endl; } else{ cout <<"NO 0."<<s3<<"*10^"<<e1 <<" 0."<<s4<<"*10^"<<e2<<endl; } return 0; }
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