List集合删除方法
Posted MR_CHW
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class Program { private static Random random = new Random((int)DateTime.Now.Ticks); static void Main(string[] args) { Console.WriteLine("Be patient, generating data..."); List<string> list = new List<string>(); List<string> toRemove = new List<string>(); for (int x = 0; x < 1000000; x++) { string randString = RandomString(random.Next(100)); list.Add(randString); if (random.Next(1000) == 0) toRemove.Insert(0, randString); } List<string> l1 = new List<string>(list); List<string> l2 = new List<string>(list); List<string> l3 = new List<string>(list); List<string> l4 = new List<string>(list); List<string> l5 = new List<string>(list); Console.WriteLine("Be patient, testing..."); Stopwatch sw1 = Stopwatch.StartNew(); l1.RemoveAll(toRemove.Contains); sw1.Stop(); Stopwatch sw2 = Stopwatch.StartNew(); l2.RemoveAll(new HashSet<string>(toRemove).Contains); sw2.Stop(); Stopwatch sw3 = Stopwatch.StartNew(); l3 = l3.Except(toRemove).ToList(); sw3.Stop(); Stopwatch sw4 = Stopwatch.StartNew(); l4 = l4.Except(new HashSet<string>(toRemove)).ToList(); sw4.Stop(); //Stopwatch sw5 = Stopwatch.StartNew(); //l5 = l5.RemoveAll((x)=>x[0]==); //sw5.Stop(); Console.WriteLine("L1.Len = {0}, Time taken: {1}ms", l1.Count, sw1.Elapsed.TotalMilliseconds); Console.WriteLine("L2.Len = {0}, Time taken: {1}ms", l1.Count, sw2.Elapsed.TotalMilliseconds); Console.WriteLine("L3.Len = {0}, Time taken: {1}ms", l1.Count, sw3.Elapsed.TotalMilliseconds); Console.WriteLine("L4.Len = {0}, Time taken: {1}ms", l1.Count, sw4.Elapsed.TotalMilliseconds); Console.ReadKey(); // //authorsList.RemoveAll((x) => x.firstname == "Bob"); //authorsList = authorsList.Except(authors).ToList(); } private static string RandomString(int size) { StringBuilder builder = new StringBuilder(); char ch; for (int i = 0; i < size; i++) { ch = Convert.ToChar(Convert.ToInt32(Math.Floor(26 * random.NextDouble() + 65))); builder.Append(ch); } return builder.ToString(); } }
备注:这是网上找的例子大致方案就是这几种,具体使用哪种看自己的实际需求
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