HDU 5366 The mook jong

Posted 2020-10-06 Reqaw’s Blog

题目链接：

http://acm.hdu.edu.cn/showproblem.php?pid=5366

Problem Description


ZJiaQ want to become a strong man, so he decided to play the mook jong。ZJiaQ want to put some mook jongs in his backyard. His backyard consist of n bricks that is 1*1,so it is 1*n。ZJiaQ want to put a mook jong in a brick. because of the hands of the mook jong， the distance of two mook jongs should be equal or more than 2 bricks. Now ZJiaQ want to know how many ways can ZJiaQ put mook jongs legally(at least one mook jong).

 

Input

There ar multiply cases. For each case, there is a single integer n( 1 < = n < = 60)

 

Output

Print the ways in a single line for each case.

 

Sample Input

1

2

3

4

5

6

Sample Output

1

2

3

5

8

12

题意描述：

输入砖数n( 1 < = n < = 60)

计算并输出有多少种合法的放器材的方法（至少有一个器材）

解题思路：

首先想到的是数据范围是1到60，打表解决。

具体打表过程中刚开始想的是有一个公式计算，就一直在总结那个公式，花费了好多时间，其实这种题直接列出来找规律递推即可。

另外，最好将数组定义为long long不容易溢出，也更为保险。

AC代码：

 1 #include<stdio.h>
 2 int main()
 3 {
 4     int n,sum,i;
 5     long long f[60];//int类型55以上出现错误，改为long long 
 6     f[1]=1;
 7     f[2]=2;
 8     f[3]=3;
 9     for(i=4;i<=60;i++)
10         f[i]=f[i-1]+f[i-3]+1;
11     while(scanf("%d",&n) != EOF)
12     {
13         printf("%lld\n",f[n]);
14     }
15     return 0;
16 }