Puzzle UVA - 227

Posted 2020-09-29 啦啦啦

A children’s puzzle that was popular 30 years ago consisted of a 5×5 frame which contained 24 small squares of equal size. A unique letter of the alphabet was printed on each small square. Since there were only 24 squares within the frame, the frame also contained an empty position which was the same size as a small square. A square could be moved into that empty position if it were immediately to the right, to the left, above, or below the empty position. The object of the puzzle was to slide squares into the empty position so that the frame displayed the letters in alphabetical order.
The illustration below represents a puzzle in its original con?guration and in its con?guration after the following sequence of 6 moves:
1) The square above the empty position moves. 2) The square to the right of the empty position moves. 3) The square to the right of the empty position moves. 4) The square below the empty position moves. 5) The square below the empty position moves. 6) The square to the left of the empty position moves.
Write a program to display resulting frames given their initial con?gurations and sequences of moves.
Input
Input for your program consists of several puzzles. Each is described by its initial con?guration and the sequence of moves on the puzzle. The ?rst 5 lines of each puzzle description are the starting con?guration. Subsequent lines give the sequence of moves.
The ?rst line of the frame display corresponds to the top line of squares in the puzzle. The other lines follow in order. The empty position in a frame is indicated by a blank. Each display line contains exactly 5 characters, beginning with the character on the leftmost square (or a blank if the leftmost square is actually the empty frame position). The display lines will correspond to a legitimate puzzle.
The sequence of moves is represented by a sequence of As, Bs, Rs, and Ls to denote which square moves into the empty position. A denotes that the square above the empty position moves; B denotes that the square below the empty position moves; L denotes that the square to the left of the empty position moves; R denotes that the square to the right of the empty position moves. It is possible that there is an illegal move, even when it is represented by one of the 4 move characters. If an illegal move occurs, the puzzle is considered to have no ?nal con?guration. This sequence of moves may be spread over several lines, but it always ends in the digit 0. The end of data is denoted by the character Z.
Output
Output for each puzzle begins with an appropriately labeled number (Puzzle #1, Puzzle #2, etc.). If the puzzle has no ?nal con?guration, then a message to that e?ect should follow. Otherwise that ?nal con?guration should be displayed.
Format each line for a ?nal con?guration so that there is a single blank character between two adjacent letters. Treat the empty square the same as a letter. For example, if the blank is an interior position, then it will appear as a sequence of 3 blanks — one to separate it from the square to the left, one for the empty position itself, and one to separate it from the square to the right.
Separate output from di?erent puzzle records by one blank line.
Note: The ?rst record of the sample input corresponds to the puzzle illustrated above.
Sample Input
TRGSJ XDOKI M VLN WPABE UQHCF ARRBBL0 ABCDE FGHIJ KLMNO PQRS TUVWX AAA LLLL0 ABCDE FGHIJ KLMNO PQRS TUVWX AAAAABBRRRLL0 Z
Sample Output
Puzzle #1: T R G S J X O K L I M D V B N W P A E U Q H C F
Puzzle #2: A B C D F G H I E K L M N J P Q R S O T U V W X
Puzzle #3: This puzzle has no final configuration.

 1 #include<iostream>
 2 #include<algorithm>
 3 #include<cstring>
 4 #include<string>
 5 #include<cstdio> 
 6 using namespace std;
 7 
 8 int main()
 9 {   int t=0;
10     bool line=false;
11     char map[5][5];
12     while(true){
13         gets(map[0]);
14         if(map[0][0]==‘Z‘) break;
15         for(int i=1;i<5;i++) gets(map[i]);
16         
17         int x=0,y=0;
18         for(int i=0;i<5;i++){
19             for(int j=0;j<5;j++){
20                 if(map[i][j]==‘ ‘) x=i,y=j;
21             }
22         }
23     
24         char a[1000];
25         bool flag=true;
26         while(true){
27             gets(a);      //key point! key point! key point!
28             for(int i=0;a[i]!=0;i++){
29                 if(a[i]==‘0‘) goto loop;
30                 if(flag){
31                     if(a[i]==‘A‘){
32                         if(x==0) flag=false;        
33                         else{
34                             map[x][y]=map[x-1][y];
35                             map[x-1][y]=‘ ‘;
36                             x--;
37                         }
38                     }
39                     if(a[i]==‘B‘){
40                         if(x==4) flag=false;    
41                         else{
42                             map[x][y]=map[x+1][y];
43                             map[x+1][y]=‘ ‘;
44                             x++;
45                         }
46                     }
47                     if(a[i]==‘L‘){
48                         if(y==0) flag=false;
49                         else{
50                             map[x][y]=map[x][y-1];
51                             map[x][y-1]=‘ ‘;
52                             y--;
53                         }
54                     }
55                     if(a[i]==‘R‘){
56                         if(y==4) flag=false;
57                         else{
58                             map[x][y]=map[x][y+1];
59                             map[x][y+1]=‘ ‘;
60                             y++;
61                         }
62                     }
63                 }
64             }
65         }
66         loop:
67         
68         if (line)
69             printf ("\n");
70         line = true;
71             
72         printf("Puzzle #%d:\n",++t);
73         if(flag)
74             for(int i=0;i<5;i++) printf("%c %c %c %c %c\n",map[i][0],map[i][1],map[i][2],map[i][3],map[i][4]);
75         else cout<<"This puzzle has no final configuration."<<endl;
76     }
77     return 0;
78 }