猜数字游戏的提示
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题目来自刘汝佳编著的《算法竞赛入门经典(第二版)》
题目描述:
我的代码:
#include<iostream> #include<cstring> using namespace std; int main() { int answer[100]; int copy[100]; int enter[100]; int n, a, b; int count = 0; n = 1; while (n != 0) { cin >> n; for (int i = 0; i < n; i++) cin >> answer[i]; cout << "Game " << ++count << endl; while (1) { a = b = 0; for (int i = 0; i < n; i++) copy[i] = answer[i]; for (int i = 0; i < n; i++) cin >> enter[i]; if (enter[0] == 0) break; for (int i = 0; i < n; i++) { if (copy[i] == enter[i]) { a++; enter[i] = copy[i] = 0; } } for (int i = 0; i < n; i++) { for (int j = 0; j < n; j++) { if (copy[i] == enter[j] && i != j && enter[j] != 0) { b++; enter[j] = copy[i] = 0; } } } cout << "\\t" << "(" << a << "," << b << ")" << endl; } } return 0; }
答案的代码:
#include<stdio.h> #define maxn 1010 int main() { int n, a[maxn], b[maxn]; int kase = 0; while (scanf("%d", &n) == 1 && n) { printf("Game %d:\\n", ++kase); for (int i = 0; i < n; i++) scanf("%d", &a[i]); for (;;) { int A = 0, B = 0; for (int i = 0; i < n; i++) { scanf("%d", &b[i]); if (a[i] == b[i]) A++; } if (b[0] == 0) break; for (int d = 1; d <= 9; d++) { int c1 = 0, c2 = 0; for (int i = 0; i < n; i++) { if (a[i] == d) c1++; if (b[i] == d) c2++; } if (c1 < c2) B += c1; else B += c2; } printf(" (%d, %d)\\n", A, B - A); } } return 0; }
这次博主有点懒。。。题目就截图贴上去了,博主做完本题之后感觉。。。自己的算法不是很精妙,答案的思路很清奇,有没有大神能贡献自己的算法呢??╮(╯▽╰)╭
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