561. Array Partition I

Posted 2020-09-26

Given an array of 2n integers, your task is to group these integers into n pairs of integer, say (a1, b1), (a2, b2), ..., (an, bn) which makes sum of min(ai, bi) for all i from 1 to n as large as possible.

Example 1:

Input: [1,4,3,2]

Output: 4
Explanation: n is 2, and the maximum sum of pairs is 4 = min(1, 2) + min(3, 4).

 

Note:

1. n is a positive integer, which is in the range of [1, 10000].
2. All the integers in the array will be in the range of [-10000, 10000].

在两个数中取最小值，令这些最小值之和最大

 

C++（82ms）：

class Solution {
public:
    int arrayPairSum(vector<int>& nums) {
        sort(nums.begin(),nums.end()) ;
        int sum = 0 ;
        for (int i = 0 ; i < nums.size() ; i+=2)
            sum += nums[i] ;
        return sum ;
    }
};