hdu 2085

Posted 2020-06-21 庸人自扰扰

PS:递推题..  a[n]=a[n-1]*3+2*b[n-1]  b[n]=a[n-1]+b[n-1] 

代码:

#include "stdio.h"
long long a[35];
long long b[35];
int main(){
    int i,c;
    a[0]=1;
    b[0]=0;
    for(i=1;i<35;i++){
        a[i]=3*a[i-1]+2*b[i-1];
        b[i]=b[i-1]+a[i-1];
    }
    while(~scanf("%d",&c)){
        if(c==-1) return 0;
        printf("%lld, %lld\n",a[c],b[c]);
    }
    return 0;
}