程序实践：命令行之连连看

Posted 2020-09-20 jhcelue

命令行之连连看

程序实践周课题，VC++6.0上可编译执行

游戏截图：

#include <cstdio>

#include <cstring>
#include <iostream>
#include <windows.h> 
#include <time.h>
#include <algorithm>
using namespace std;
int dirx[4] = {1,-1,0,0};  
int diry[4] = {0,0,1,-1};  //四个方向，DFS函数中要使用
bool vis[15][15];	//标记该点是否已经被訪问，DFS中使用
char map[15][15];	//二维字符数组表示连连看矩阵
bool Hash[105];  //hash数组用来标记，去重
int num, level;		//num游戏记录人数。 level游戏等级
char choose[100];		//提取对应操作的字符
struct Players  //结构体存游戏者的帐号，得分，排名
{
	char name[50];
	int score;
	int rank;
};
struct Data
{
	int n;
	struct Players player[100];
}data[4];


bool cmp(Players a, Players b)
{
	return a.score < b.score;
}

void set_rank(int l)
{
	int tmp;
	if (l == 4)
		tmp = 0;
	else if (l == 6)
		tmp = 1;
	else if (l == 8)
		tmp = 2;
	else if (l == 10)
		tmp = 3;
	for(int i = 0; i < data[tmp].n; i++)
	{
		data[tmp].player[i].rank = i + 1;
		if(data[tmp].player[i].score == data[tmp].player[i + 1].score)
		{
			data[tmp].player[i + 1].rank = data[tmp].player[i].rank;
			i++;
		}
	}
}

void menu()  //菜单
{
	HANDLE handle = GetStdHandle(STD_OUTPUT_HANDLE);
	SetConsoleTextAttribute(handle, FOREGROUND_INTENSITY | FOREGROUND_RED | FOREGROUND_GREEN);
	printf("\n\n			*********************************\n");
	SetConsoleTextAttribute(handle, FOREGROUND_INTENSITY | FOREGROUND_RED);
	printf("			*****    欢迎进入 连连看    *****\n");
	SetConsoleTextAttribute(handle, FOREGROUND_INTENSITY | FOREGROUND_RED | FOREGROUND_GREEN);
	printf("			*****    C - 选择游戏等级   *****\n");
	printf("			*****    T - 有时间限定     *****\n");
	printf("			*****    N - 无时间限定     *****\n");
	printf("			*****    R - 玩家排名       *****\n");
	printf("			*****    E - 游戏结束       *****\n");
	printf("			*********************************\n\n");
	if(level == 0)
		printf("			*****    游戏等级 : 未选    *****\n");
	else if(level == 4)
		printf("			*****    游戏等级 : 低级    *****\n");
	else if(level == 6)
		printf("			*****    游戏等级 : 中级    *****\n");
	else if(level == 8)
		printf("			*****    游戏等级 : 高级    *****\n");
	else if(level == 10)
		printf("			*****    游戏等级 : 特高    *****\n");
	printf("\n输入操作 : ");
	scanf("%s", &choose);
	//printf("choose = %c\n", choose);
	//system("PAUSE");
	system("CLS"); //清屏函数
	//清屏后显示菜单

}

void ChooseMenu()
{
	int tmp;
	//设4个等级。通过选择游戏难度初始化level
	printf("\n\n			********************************\n");
	printf("			*****        选择等级      *****\n");
	printf("			*****        1 - 低级      *****\n"); // 4 * 4
	printf("			*****        2 - 中级      *****\n"); // 6 * 6
	printf("			*****        3 - 高级      *****\n"); // 8 * 8
	printf("			*****        4 - 特高      *****\n"); // 10 * 10
	printf("			********************************\n");
	printf("		  \n游戏等级 ： ");
	scanf("%d", &tmp);
	while(tmp != 1 && tmp != 2 && tmp != 3 && tmp != 4)
	{
		printf("			请选择正确的游戏等级 1 , 2 , 3 , 4\n");
		printf("		  \n游戏等级 ： ");
		scanf("%d", &tmp);
	}
	if (tmp == 1)
		level = 4;
	else if (tmp == 2)
		level = 6;
	else if (tmp == 3)
		level = 8;
	else if (tmp == 4)
		level = 10;
	getchar();
}

void init_map()  //初始化游戏矩阵
{
	int i, j;
	char get[105];	 //get数组用来得到随机字符
	memset(Hash, false, sizeof(Hash)); //初始化hash数组
	srand((unsigned)time(NULL));	//设置随机数种子
	//随机生成一半的字符。由于要保证两两配对
	for(i = 0; i < (level * level) / 2; i++) 
	{
		get[i] = 65 + rand() % 26;   //随机生成前一半
		get[i + (level * level) / 2] = get[i]; //将前一半的值赋给后一半
	}
	int index;  //在get中随机产生的数组下标
	bool flag;	//标记是否找到一个新的字符
	srand((unsigned)time(NULL)); //设置随机数种子
	for(i = 1; i <= level; i++)
	{
		for(j = 1; j <= level; j++)
		{
			flag = false;   //flag每次先赋值为false
			while(true)		//死循环
			{
				index = 0 + rand() % (level * level); //随机生成get数组中的下标
				if(!Hash[index])	//	假设该点没有被使用
				{	
					map[i][j] = get[index];  //将它的值赋给map
					Hash[index] = true;		 //将它标记为已使用
					flag = true;			 //找到一个字符flag设为true
				}
				if(flag)  //假设找到则退出for循环
					break;
			}
		}
	}
	//在连连看矩阵周围加一圈空格，用来消除边界元素
	for(i = 0; i <= level + 1; i++)
		map[0][i] = map[level + 1][i] = map[i][0] = map[i][level +1] = ‘ ‘;
}

void show_map()   //显示矩阵
{
	HANDLE handle = GetStdHandle(STD_OUTPUT_HANDLE);
	printf("\n\n\n");
	int i, j;
	SetConsoleTextAttribute(handle, FOREGROUND_INTENSITY | FOREGROUND_RED);
	printf("	");
	for(i = 1; i <= level; i++)
		printf("%4d", i);
	SetConsoleTextAttribute(handle, FOREGROUND_INTENSITY | FOREGROUND_GREEN);
	printf("	游戏选择");
	printf("\n\n");
	for(i = 1; i <= level; i++)
	{
		SetConsoleTextAttribute(handle, FOREGROUND_INTENSITY | FOREGROUND_RED | FOREGROUND_GREEN);
		printf("	");
		for(j = 1; j <= level; j++)
			printf("%4c", map[i][j]);
		SetConsoleTextAttribute(handle, FOREGROUND_INTENSITY | FOREGROUND_RED);
		printf("%4d", i);
		SetConsoleTextAttribute(handle, FOREGROUND_INTENSITY | FOREGROUND_GREEN);
		if (i == 1)
			printf("	T - 提示\n\n");
		else if (i == 2)
			printf("	R - 洗牌\n\n");
		else if (i == 3)
			printf("	C - 继续\n\n");
		else
			printf("\n\n");
	}
	SetConsoleTextAttribute(handle, FOREGROUND_INTENSITY | FOREGROUND_GREEN);
}


bool IsWin()  //推断是否结束
{
	int i, j;
	for(i = 1; i <= level; i++)
		for(j = 1; j <= level; j++)
			if(map[i][j] != ‘ ‘) //假设矩阵中有一个不是空格则说明没有结束
				return false;
	return true;
}

bool DFS(int x1, int y1, int x2, int y2, int turn, int dir)
{
    //转向次数大于2则返回false。这里大于3是由于dir初始为-1也就是第一次选方向时
    //就已经让turn加1了，
    if(turn > 3)
        return false;
    //转向两次后不能沿某一方向到终点，返回false
    if(turn == 3 && (x2 != x1 && y2 != y1))
        return false;
    //到达终点，返回true
    if(x1 == x2 && y1 == y2)
        return true;
    for(int i = 0; i < 4; i++) //四个方向遍历
    {
        int xx = x1 + dirx[i];
        int yy = y1 + diry[i];
        //若该点有字符且不是终点则换方向
        if(map[xx][yy] != ‘ ‘ && !(xx == x2 && yy == y2))
            continue;
		//推断是否出界，是否已经訪问
        if(xx < 0 || yy < 0 || xx > level + 1 || yy > level + 1 || vis[xx][yy])
            continue;   
        //将该点设为已訪问
        vis[xx][yy] = true;
        //若当前方向与之前方向不同，转向次数＋1，继续搜索
        if(DFS(xx, yy, x2, y2, turn + (dir != i), i))
            return true;
        //若从该点的dfs不成功，将该点设为未訪问
        vis[xx][yy] = false;
    }
    return false;
}


bool judge(int x1, int y1, int x2, int y2)
{
	memset(vis, false, sizeof(vis)); //初始化vis数组用于DFS
	vis[x1][y1] = true;	//将起点标记为已訪问
	//特判几种不能消除的情况
	if(x1 == x2 && y1 == y2)
	{
		printf("\n	输入的两点坐标同样，请保证两点的坐标不同\n\n");
		return false;
	}
	if(map[x1][y1] == ‘ ‘ || map[x2][y2] == ‘ ‘)
	{
		printf("\n	两点之中有没有图案的点，请保证两点都有图案\n\n");
		return false;
	}
	if(map[x1][y1] != map[x2][y2])
	{
		printf("\n	两点图案不同。请保证两点图案同样\n\n");
		return false;
	}
	if(DFS(x1, y1, x2, y2, 0, -1))
	{
		printf("\n	这两点能够消除\n\n");
		return true;
	}
	else
	{
		printf("这两点不能消除。请重试\n\n");
		return false;
	}
} 


//该函数在total_judge()中被调用。功能与judge相似
//不输出中文提示
bool judge2(int x1, int y1, int x2, int y2) 
{
	memset(vis, false, sizeof(vis));
	vis[x1][y1] = true;
	if(x1 == x2 && y1 == y2)
		return false;
	if(map[x1][y1] == ‘ ‘ || map[x2][y2] == ‘ ‘)
		return false;
	if(map[x1][y1] != map[x2][y2])
		return false;
	if(DFS(x1, y1, x2, y2, 0, -1))
		return true;
	return false;
}


bool total_judge()  //全盘判定，用于推断是否还有可行解
{
	int i, j, ii, jj;
	bool vis2[15][15];   //标记该点是否被訪问
	memset(vis2, false, sizeof(vis2)); //初始化vis2
	int x1, y1, x2, y2;  //记录两个点的坐标
	for(i = 1; i <= level; i++)
	{
		for(j = 1; j <= level; j++)
		{
			//假设该点不是空格，而且没有被訪问
			if(map[i][j] != ‘ ‘ && !vis2[i][j])
			{
				vis2[i][j] = true; //将其设为已訪问
				//找到一个点A赋值
				x1 = i;		
				y1 = j;
				//printf("x1 = %d  y1 = %d\n", x1, y1);
				//枚举点找到与A点字符同样的一个点
				for(ii = 1; ii <= level; ii++)
				{
					for(jj = 1; jj <= level; jj++)
					{
						if(map[ii][jj] == map[x1][y1] && !vis2[ii][jj])
						{
							//假设找到一个点与A点不是同一点而且图案同样
							//将其标记为已訪问
							vis2[ii][jj] = true;
							//记为B点并赋值
							x2 = ii;
							y2 = jj;
							//printf("x2 = %d  y2 = %d\n", x2, y2);
							//推断A，B是否能被消除
							//找到一个可行解则说明游戏能够继续不用restart
							if(judge2(x1, y1, x2, y2))
								return true;
						}
					}
				}
			}
		}
	}
	//假设没找到可行解。则须要restart
	return false;
}


bool Tip()  //全盘判定，用于推断是否还有可行解
{
	int i, j, ii, jj;
	bool vis2[15][15];   //标记该点是否被訪问
	memset(vis2, false, sizeof(vis2)); //初始化vis2
	int x1, y1, x2, y2;  //记录两个点的坐标
	for(i = 1; i <= level; i++)
	{
		for(j = 1; j <= level; j++)
		{
			//假设该点不是空格，而且没有被訪问
			if(map[i][j] != ‘ ‘ && !vis2[i][j])
			{
				vis2[i][j] = true; //将其设为已訪问
				//找到一个点A赋值
				x1 = i;		
				y1 = j;
				//枚举点找到与A点字符同样的一个点
				for(ii = 1; ii <= level; ii++)
				{
					for(jj = 1; jj <= level; jj++)
					{
						if(map[ii][jj] == map[x1][y1] && !vis2[ii][jj])
						{
							//假设找到一个点与A点不是同一点而且图案同样
							//将其标记为已訪问
							vis2[ii][jj] = true;
							//记为B点并赋值
							x2 = ii;
							y2 = jj;
							//推断A，B是否能被消除
							//找到一个可行解则说明游戏能够继续不用restart
							if(judge2(x1, y1, x2, y2))
							{
								//输出可行解
								printf("\n	提示 :\n	x1 = %d, y1 = %d\n	x2 = %d, y2 = %d\n", x1, y1, x2, y2);
								return true;
							}
						}
					}
				}
			}
		}
	}
	return false;
}

void Restart() //洗牌函数
{
	int i, j;
	bool hash2[105], flag;
	char re[105];
	int cnt = 0, index2;
	memset(re, 0, sizeof(re));
	memset(hash2, false, sizeof(hash2));
	for(i = 1; i <= level; i++)
		for(j = 1; j <= level; j++)
			if(map[i][j] != ‘ ‘) 
				re[cnt++] = map[i][j]; //提取实用字符
	
	srand((unsigned)time(NULL));
	for(i = 1; i <= level; i++)
	{
		for(j = 1; j <= level; j++)
		{
			if (map[i][j] != ‘ ‘)
			{
				flag = false;
				while (true)
				{
					index2 = 0 + rand() % cnt;
					if (!hash2[index2])
					{
						hash2[index2] = true;
						map[i][j] = re[index2];
						flag = true;
					}
					if (flag)
						break;
				}
			}
		}
	}
}


void Rank()
{
	printf("\n\n");
	for (int i = 0; i < 4; i++)
	{
		if (i == 0)
		{
			printf("		低级：\n");
			printf("		排名		账号		成绩(秒)\n");
			for (int j = 0; j < data[i].n; j++)
				printf("		%d		%s		%d\n", data[i].player[j].rank, data[i].player[j].name, data[i].player[j].score / 1000);
			printf("\n");
		}
		if (i == 1)
		{
			printf("		中级：\n");
			printf("		排名		账号		成绩(秒)\n");
			for (int j = 0; j < data[i].n; j++)
				printf("		%d		%s		%d\n", data[i].player[j].rank, data[i].player[j].name, data[i].player[j].score / 1000);
			printf("\n");
		}
		if (i == 2)
		{
			printf("		高级：\n");
			printf("		排名		账号		成绩(秒)\n");
			for (int j = 0; j < data[i].n; j++)
				printf("		%d		%s		%d\n", data[i].player[j].rank, data[i].player[j].name, data[i].player[j].score / 1000);
			printf("\n");
		}
		if (i == 3)
		{
			printf("		特高：\n");
			printf("		排名		账号		成绩(秒)\n");
			for (int j = 0; j < data[i].n; j++)
				printf("		%d		%s		%d\n", data[i].player[j].rank, data[i].player[j].name, data[i].player[j].score / 1000);
			printf("\n");
		}
	}
	system("PAUSE");
}


int GameMenuChoose()
{
	printf("\n	输入操作 : ");
	char tmp;
	getchar();
	scanf("%c", &tmp);
	if (tmp == ‘T‘)
	{
		Tip();
		return 1;
	}
	if (tmp == ‘R‘)
	{
		system("CLS");
		Restart();
		show_map();
		return 1;
	}
	if (tmp == ‘C‘)
		return 0;
	return 0;
}

void play() //游戏函数
{
	int x1, y1, x2, y2;
	while (GameMenuChoose());
	printf("\n	请输入两点坐标\n");
	printf("\n	一 : ");
	scanf("%d %d", &x1, &y1);
	printf("\n	二 : ");
	scanf("%d %d", &x2, &y2);
	if (judge(x1, y1, x2, y2))  //假设能够消除，把两点的值设为空格
	{
		map[x1][y1] = ‘ ‘;
		map[x2][y2] = ‘ ‘;
	}
}


void Start()
{
	system("CLS");
	init_map();  //初始化游戏界面
	while (!IsWin())  //假设游戏没有结束则一直play
	{
		while (!total_judge())	//若没有可行解，则一直洗牌直到有可行解
		{
			Restart();
			show_map();
		}
		show_map();
		play();
		system("PAUSE");
		system("CLS");
	}
	system("CLS");
	printf("Good Job!\n");
	system("PAUSE");
	system("CLS");
}

void ReadInMemory(Data *u)
{
	FILE *fp;
	fp = fopen("data.txt", "rb");
	if (fp == NULL)
		return;
	fread(u, sizeof(struct Data), 1, fp);
	fclose(fp);
}

void WriteToFile(Data * u)
{
	FILE *fp;
	fp = fopen("data.txt", "wb");
	if (fp == NULL)
		return;
	fwrite(u, sizeof(struct Data), 1, fp);
	fclose(fp);
}

void SetData(int l,int e, int s, char *a)
{
	if (l == 4)
	{
		data[0].n++;
		data[0].player[data[0].n].score = (int)e - s;
		strcpy(data[0].player[data[0].n].name, a);
		sort(data[0].player, data[0].player + data[0].n, cmp);
	}
	else if (l == 6)
	{
		data[1].n++;
		data[1].player[data[1].n].score = (int)e - s;
		strcpy(data[1].player[data[1].n].name, a);
		sort(data[1].player, data[1].player + data[1].n, cmp);
	}
	else if (l == 8)
	{
		data[2].n++;
		data[2].player[data[2].n].score = (int)e - s;
		strcpy(data[2].player[data[2].n].name, a);
		sort(data[2].player, data[2].player + data[2].n, cmp);
	}
	else if (l == 10)
	{
		data[3].n++;
		data[3].player[data[3].n].score = (int)e - s;
		strcpy(data[3].player[data[3].n].name, a);
		sort(data[3].player, data[3].player + data[3].n, cmp);
	}
}


int main()
{
	//system("title 连连看");
	level = 0;
Loop:
	char tmp_name[20];
	ReadInMemory(data);
	menu();
	if(choose[0] == ‘E‘)
		return 0;
	if(choose[0] == ‘R‘)
	{
		Rank();
		system("CLS");
		goto Loop;
	}
	if(choose[0] == ‘C‘)
	{
		system("CLS");
		ChooseMenu();
		system("PAUSE");
		system("CLS");
		goto Loop;
	}
	if (level == 0 && (choose[0] == ‘N‘ || choose[0] == ‘T‘))
	{
		while (choose[0] != ‘C‘)
		{
			system("CLS");
			printf("\n\n				请先选择游戏等级\n");
			ChooseMenu();
			system("PAUSE");
			if (level != 0)
			{
				system("CLS");
				break;
			}
		}
		goto Loop;
	}
	if (choose[0] == ‘N‘)
	{
		Start();
		goto Loop;
	}
	if (choose[0] == ‘T‘)
	{
		printf("请输入username\n");
		cin >> tmp_name;
		clock_t st = clock();
		Start();
		clock_t ed = clock();
		SetData(level, st, ed, tmp_name);
		set_rank(level);
		WriteToFile(data);
		goto Loop;
	}
	if(strlen(choose) != 1 || choose[0] != ‘E‘ || choose[0] != ‘R‘ || choose[0] != ‘C‘ || choose[0] != ‘N‘ || choose[0] != ‘T‘)
	{
		printf("非法输入，请看清菜单选项\n");
		system("PAUSE");
		system("CLS");
		goto Loop;
	}
	return 0;
}