例题作业

Posted 2020-09-09 zhangyi12

1.#include<stdio.h>
#include<stdlib.h>
main()
{
struct student
{int num;
char name[20];
char sex;
int age;
float score;
char addr[30]; 
};
}

2.#include<stdio.h>
#include<stdlib.h>
main()
{
struct Date 
{
int month;
int day;
int year;
};
struct Student 
{
int num;
char name[20];
char sex;
int age;
struct Date birthday;
char addr[30];
};
}

#include <stdio.h>
#include <string.h>
int main()
{
struct student
{
long num;
char name[20];
char sex;
float score;
};
struct student stu1;
struct student *p;
p=&stu1;
stu1.num=10101;
strcpy(stu1.name, "Li Lin"); 
stu1.sex=\'M\';
stu1.score=89.5;
printf("No.:%1d\\nname:%s\\nsex:%c\\nscore:%5.1f\\n",stu1.num,stu1.name,stu1.sex,stu1.score);
printf("\\nNo.:%1d\\nname:%s\\nsex:%c\\nscore:%5.1f\\n",(*p).num,(*p).name,(*p).sex,(*p).score);
return 0;}

#include <stdio.h>
struct student
{
int num;
char name[20];
char sex;
int age;
};
struct student stu[3]={{10101,"Li Lin",\'M\',18},{10102,"Zhang Fang",\'M\',19},{10103,"Wang Min",\'F\',20}};
int main()
{
struct student *p;
p = stu; 
printf("No. Name sex age\\n");
for (p=stu;p<stu+3;p++)
printf("%5d %-20s%2c%4d\\n",p->num,p->name,p->sex,p->age);}

#include<stdio.h>
#define N 3 
struct Student//声明结构体类型 struct person 
{
int num;
char name[20];
float score[3];//三门课成绩 
float aver;//平均成绩 
};
int main()
{void input(struct Student stu[]);
struct Student max(struct Student stu[]);
void print(struct Student stu);
struct Student stu[N],*p=stu;//定义结构体数组和指针 
input(p);//调用input函数 
print(max(p));//调用print函数，以max函数的返回值作为实参 
return 0;
}
void input(struct Student stu[])
{int i;
printf("请输入个学生的信息：学号，姓名，三门课成绩：\\n");
for(i=0;i<N;i++)
{scanf("%d,%s,%f,%f,%f",&stu[i].num,stu[i].name,&stu[i].score[0],&stu[i].score[1],&stu[i].score[2]);//输入数据 
stu[i].aver=(stu[i].score[0]+stu[i].score[1]+stu[i].score[2])/3.0;//求平均值 
}
}
struct Student max(struct Student stu[])
{int i,m=0;//用m存放成绩最高的学生在数组中的序号 
for(i=0;i<N;i++)
if(stu[i].aver>stu[m].aver)m=i;
return stu[m];//返还值包含该生信息的结构体元素 
}
void print(struct Student stud)
{printf("\\n成绩最好的学生是：\\n");
printf("学号：%d\\姓名：%s\\n三门课成绩：%5.1f,%5.1f,%5.1f\\n平均成绩：%6.2f，stud.num,stud.name,stud.score[0],stud.score[1],stud.score[2],stud.aver");}

 

3.#include<stdio.h>
#include<stdlib.h>
main()
{

struct Student 
{
int num;
char name[20];
char sex;
int age;
float score;
char addr[30];
}student1,student2;}

4.#include<stdio.h>
#include<stdlib.h>
main()
{struct Student
{long int num;
char name[20];
char sex;
char addr[20];
}a={10101,"zhangyi",\'man\',"bijie"};
printf("NO.;%ld\\nname:%s\\nsex:%c\\naddress:%s\\n",a.num,a.name,a.sex,a.addr);
return 0;}

5.#include<stdio.h>
#include<stdlib.h>
main()
{struct Student
{int num;
char name[20];
float score;
}student1,student2;
scanf("%d,%s,%f",&student1.num,&student1.name,&student1.score);
scanf("%d,%s,%f",&student2.num,&student2.name,&student2.score);
printf("The higher score is:\\n");
if(student1.score>student2.score)
printf("%d,%s,%f",student1.num,student1.name,student1.score);
else if(student1.score<student2.score)
printf("%d,%s,%f",student2.num,student2.name,student2.score);
else
{printf("%d,%s,%f",student1.num,student1.name,student1.score);
printf("%d,%s,%f",student2.num,student2.name,student2.score);
}
return 0;}

6.

#include <stdio.h>
struct student
{
int num;
char name[20];
float score;
};
int main()
{
struct student stu[5]={{ 10101,"zhang",78},{10103,"wang",98.5},{10106,"li",86},{ 10108,"ling",73.5},{ 10110,"sun",100}};
struct student temp;
const int n=5;
int i,j,k;
printf("The order is:\\n");
for(i=0;i<n-1;i++)
{k=i;
for(j=i+1;j<n;j++)
if(stu[j].score>stu[k].score)
k=j;
temp=stu[k];stu[k]=stu[i];stu[i]=temp;
}
for(i=0;i<n;i++)
printf("%6d %8s %6.2f\\n",stu[i].num,stu[i].name,stu[i].score);
printf("\\n");
return 0;}

 

#include<string.h>
#include<stdio.h>
struct person
{
char name[20];
int count;
}leader[3]={"zhang",0,"jun",0,"jie",0};
int main()
{
int i,j;
char leader_name[20];
for(i=1;i<=10;i++)
{
scanf("%s",leader_name);
for (j=0;j<3;j++)
if (strcmp(leader_name,leader[j].name)==0)leader[j].count++;
}
printf("\\nResult:\\n");
for(i=0;i<3;i++)
printf("%5s:%d\\n",leader[i].name,leader[i].count);}