行转列，列转行

Posted 2020-09-04 8899man

 

oracle:

 

----------------------------- 行转列  --------------------------------
select * from demo
create table demo(id int,name varchar(20),nums int);  ---- 创建表
insert into demo values(1, ‘苹果‘, 1000);
insert into demo values(2, ‘苹果‘, 2000);
insert into demo values(3, ‘苹果‘, 4000);
insert into demo values(4, ‘橘子‘, 5000);
insert into demo values(5, ‘橘子‘, 3000);
insert into demo values(6, ‘葡萄‘, 3500);
insert into demo values(7, ‘芒果‘, 4200);
insert into demo values(8, ‘芒果‘, 5500);

select * from (select name, nums from demo) pivot (sum(nums) for name in (‘苹果‘ 苹果, ‘橘子‘, ‘葡萄‘, ‘芒果‘));

 

----------------- 列转行 ----------------------
create table Fruit(id int,name varchar(20), Q1 int, Q2 int, Q3 int, Q4 int);
 
insert into Fruit values(1,‘苹果‘,1000,2000,3300,5000);
insert into Fruit values(2,‘橘子‘,3000,3000,3200,1500);
insert into Fruit values(3,‘香蕉‘,2500,3500,2200,2500);
insert into Fruit values(4,‘葡萄‘,1500,2500,1200,3500);

 

 

select * from Fruit

 

select id , name, jidu, xiaoshou from Fruit unpivot (xiaoshou for jidu in (q1, q2, q3, q4) )

 

 

 

 

sqlserver:

-----------------------行转列----------------------------------

CREATE TABLE [dbo].[tbl_Student](
    [ID] [int] IDENTITY(1,1) NOT NULL,
    [学生ID] [varchar](50) COLLATE Chinese_PRC_CI_AS NULL,
    [学生姓名] [nvarchar](50) COLLATE Chinese_PRC_CI_AS NULL,
    [课程ID] [nchar](10) COLLATE Chinese_PRC_CI_AS NULL,
    [课程名称] [nvarchar](50) COLLATE Chinese_PRC_CI_AS NULL,
    [成绩] [int] NULL,
    [教师ID] [varchar](50) COLLATE Chinese_PRC_CI_AS NULL,
    [教师姓名] [nvarchar](50) COLLATE Chinese_PRC_CI_AS NULL
) ON [PRIMARY]

insert into tbl_Student values(
‘S3‘,‘王五‘,‘K4        ‘,‘政治‘,53,‘T4‘,‘赵老师‘);
insert into tbl_Student values(
‘S1‘,‘ 张三 ‘,‘K1        ‘,‘数学‘,61,‘T1‘,‘张老师‘);
insert into tbl_Student values(
‘S2‘,‘李四‘,‘K3        ‘,‘英语‘,88,‘T3‘,‘李老师‘);
insert into tbl_Student values(
‘S1‘,‘  张三 ‘,‘K4        ‘,‘政治‘,77,‘T4‘,‘赵老师‘);
insert into tbl_Student values(
‘S2‘,‘李四‘,‘K4        ‘,‘政治‘,67,‘T5‘,‘周老师‘);
insert into tbl_Student values(
‘S3‘,‘王五‘,‘K2        ‘,‘语文‘,90,‘T2‘,‘王老师‘);
insert into tbl_Student values(
‘S3‘,‘王五‘,‘K1        ‘,‘数学‘,55,‘T1‘,‘张老师‘);
insert into tbl_Student values(
‘S1‘,‘ 张三 ‘,‘K2        ‘,‘语文‘,81,‘T2‘,‘王老师‘);
insert into tbl_Student values(
‘S4‘,‘赵六‘,‘K2        ‘,‘语文‘,59,‘T1‘,‘王老师‘);
insert into tbl_Student values(
‘S1‘,‘ 张三 ‘,‘K3        ‘,‘英语‘,37,‘T3‘,‘李老师‘);

select 学生姓名,课程ID,成绩,教师ID,教师姓名,
max(case 课程名称 when ‘政治‘ then 成绩 else 0 end) 政治, 
max(case 课程名称 when ‘语文‘ then 成绩 else 0 end) 语文,
max(case 课程名称 when ‘数学‘ then 成绩 else 0 end) 数学,
max(case 课程名称 when ‘英语‘ then 成绩 else 0 end) 英语
from tbl_Student group by 学生姓名,课程ID,成绩,教师ID,教师姓名

select *
from (select * from tbl_Student) 
a pivot (max(成绩) for 课程名称 in (语文,数学,英语,政治)) b




--------------------------列转行 -----------------------------------

CREATE TABLE [dbo].[tbl_test2](

    [UserID] [int] NULL,
    [UserNo] [int] NULL,
    [A] [int] NULL,
    [B] [int] NULL,
    [C] [int] NULL
) ON [PRIMARY]

insert into tbl_test2 values(1,1,11,22,33);

SELECT  USERID,USERNO,tType=attribute
FROM (select * from tbl_列转行测试)a
  UNPIVOT
  (
    value FOR attribute IN(A, B,C)
  ) AS UPV