DjangoDjango 如何支持 分组查询统计？

Posted 2020-08-14 junneyang 的博客

代码：

from django.db.models import Sum
        alarm_sum_group_items = models.FILE_PROTECT_ALARM.objects.filter(customer_id=customer_id).values(\'device_hash\').annotate(alarm_sum=Sum(\'cmn_merge_count\'))
        data = []
        for item in alarm_sum_group_items:
            tmp = {}
            tmp[\'customer_id\'] = customer_id
            tmp[\'device_hash\'] = item[\'device_hash\']
            tmp[\'alarm_sum\'] = item[\'alarm_sum\']
            data.append(tmp)
        return APIResponse(status=status_code.success, data=data)

 

参考资料：

https://www.douban.com/group/topic/18930354/?type=like

http://www.tuicool.com/articles/aiUBVrn

https://www.douban.com/group/topic/18930354/?type=like

http://stackoverflow.com/questions/19101665/django-how-to-do-select-count-group-by-and-order-by

https://my.oschina.net/duoduo3369/blog/199190

http://stackoverflow.com/questions/327807/django-equivalent-for-count-and-group-by

https://segmentfault.com/q/1010000005828240

 

http://www.cnblogs.com/BeginMan/archive/2013/05/27/3101322.html

http://blog.csdn.net/iloveyin/article/details/46380619

http://www.jb51.net/article/69774.htm