P3649 [APIO2014]回文串(回文自动机)

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回文自动机裸题,把PAM建出来以后对每个节点更新答案即可

代码:

#include <bits/stdc++.h>
#define int long long
#define sc(a) scanf("%lld",&a)
#define scc(a,b) scanf("%lld %lld",&a,&b)
#define sccc(a,b,c) scanf("%lld %lld %lld",&a,&b,&c)
#define schar(a) scanf("%c",&a)
#define pr(a) printf("%lld",a)
#define fo(i,a,b) for(int i=a;i<b;++i)
#define re(i,a,b) for(int i=a;i<=b;++i)
#define rfo(i,a,b) for(int i=a;i>b;--i)
#define rre(i,a,b) for(int i=a;i>=b;--i)
#define prn() printf("\n")
#define prs() printf(" ")
#define mkp make_pair
#define pii pair<int,int>
#define pub(a) push_back(a)
#define pob() pop_back()
#define puf(a) push_front(a)
#define pof() pop_front()
#define fst first
#define snd second
#define frt front()
#define bak back()
#define mem0(a) memset(a,0,sizeof(a))
#define memmx(a) memset(a,0x3f3f,sizeof(a))
#define memmn(a) memset(a,-0x3f3f,sizeof(a))
#define debug
#define db double
#define yyes cout<<"YES"<<endl;
#define nno cout<<"NO"<<endl;
using namespace std;
typedef vector<int> vei;
typedef vector<pii> vep;
typedef map<int,int> mpii;
typedef map<char,int> mpci;
typedef map<string,int> mpsi;
typedef deque<int> deqi;
typedef deque<char> deqc;
typedef priority_queue<int> mxpq;
typedef priority_queue<int,vector<int>,greater<int> > mnpq;
typedef priority_queue<pii> mxpqii;
typedef priority_queue<pii,vector<pii>,greater<pii> > mnpqii;
const int maxn=500005;
const int inf=0x3f3f3f3f3f3f3f3f;
const int MOD=100000007;
const db eps=1e-10;
int qpow(int a,int b)int tmp=a%MOD,ans=1;while(b)if(b&1)ans*=tmp,ans%=MOD;tmp*=tmp,tmp%=MOD,b>>=1;return ans;
int lowbit(int x)return x&-x;
int max(int a,int b)return a>b?a:b;
int min(int a,int b)return a<b?a:b;
int mmax(int a,int b,int c)return max(a,max(b,c));
int mmin(int a,int b,int c)return min(a,min(b,c));
void mod(int &a)a+=MOD;a%=MOD;
bool chk(int now)
int half(int l,int r)while(l<=r)int m=(l+r)/2;if(chk(m))r=m-1;else l=m+1;return l;
int ll(int p)return p<<1;
int rr(int p)return p<<1|1;
int mm(int l,int r)return (l+r)/2;
int lg(int x)if(x==0) return 1;return (int)log2(x)+1;
bool smleql(db a,db b)if(a<b||fabs(a-b)<=eps)return true;return false;
db len(db a,db b,db c,db d)return sqrt((a-c)*(a-c)+(b-d)*(b-d));
bool isp(int x)if(x==1)return false;if(x==2)return true;for(int i=2;i*i<=x;++i)if(x%i==0)return false;return true;
inline int read()
    char ch=getchar();int s=0,w=1;
    while(ch<48||ch>57)if(ch==-)w=-1;ch=getchar();
    while(ch>=48&&ch<=57)s=(s<<1)+(s<<3)+ch-48;ch=getchar();
    return s*w;

inline void write(int x)
    if(x<0)putchar(-),x=-x;
    if(x>9)write(x/10);
    putchar(x%10+48);


int ans=-inf;

struct PAM
    int tot,last,n,cur;
    int fail[maxn],len[maxn],cnt[maxn],son[maxn][26];
    char s[maxn];
    int get(int p,int x)
        while(s[x-len[p]-1]!=s[x]) p=fail[p];
        return p;
    
    int newnode(int x)
        len[tot]=x;
        return tot++;
    
    void build()
        scanf("%s",s+1);
        s[0]=-1,fail[0]=1,last=0;
        newnode(0),newnode(-1);
        for(n=1;s[n];++n)
            s[n]-=a;
            cur=get(last,n);
            if(!son[cur][s[n]])
                int now=newnode(len[cur]+2);
                fail[now]=son[get(fail[cur],n)][s[n]];
                son[cur][s[n]]=now;
            
            cnt[last=son[cur][s[n]]]++;
        
        for(int i=tot-1;i>=0;--i)
            cnt[fail[i]]+=cnt[i];
        for(int i=tot-1;i>=0;--i)
            ans=max(ans,len[i]*cnt[i]);//
    
pam;

signed main()
    ios_base::sync_with_stdio(0);
    cin.tie(0),cout.tie(0);
    pam.build();
    pr(ans);
    return 0;

 

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