codeforces 680A A. Bear and Five Cards(水题)

Posted LittlePointer

tags:

篇首语:本文由小常识网(cha138.com)小编为大家整理,主要介绍了codeforces 680A A. Bear and Five Cards(水题)相关的知识,希望对你有一定的参考价值。

题目链接:

A. Bear and Five Cards

//#include <bits/stdc++.h>
#include <vector>
#include <iostream>
#include <queue>
#include <cmath>
#include <map>
#include <cstring>
#include <algorithm>
#include <cstdio>

using namespace std;
#define Riep(n) for(int i=1;i<=n;i++)
#define Riop(n) for(int i=0;i<n;i++)
#define Rjep(n) for(int j=1;j<=n;j++)
#define Rjop(n) for(int j=0;j<n;j++)
#define mst(ss,b) memset(ss,b,sizeof(ss));
typedef long long LL;
template<class T> void read(T&num) {
    char CH; bool F=false;
    for(CH=getchar();CH<0||CH>9;F= CH==-,CH=getchar());
    for(num=0;CH>=0&&CH<=9;num=num*10+CH-0,CH=getchar());
    F && (num=-num);
}
int stk[70], tp;
template<class T> inline void print(T p) {
    if(!p) { puts("0"); return; }
    while(p) stk[++ tp] = p%10, p/=10;
    while(tp) putchar(stk[tp--] + 0);
    putchar(\n);
}

const LL mod=1e9+7;
const double PI=acos(-1.0);
const LL inf=1e14;
const int N=1e5+15;

int a[10],flag[200];
int main()
{
    int sum=0;
    for(int i=1;i<=5;i++)read(a[i]),sum+=a[i],flag[a[i]]++;
    int ans=sum;
    for(int i=1;i<=5;i++)
    {
        if(flag[a[i]]>1&&flag[a[i]]<4)
        ans=min(ans,sum-flag[a[i]]*a[i]);
        else if(flag[a[i]]>3)
        {
            ans=min(ans,sum-3*a[i]);
        }
    }
    cout<<ans<<"\n";


        return 0;
}

 

以上是关于codeforces 680A A. Bear and Five Cards(水题)的主要内容,如果未能解决你的问题,请参考以下文章

CodeForces 653 A. Bear and Three Balls——(IndiaHacks 2016 - Online Edition (Div. 1 + Div. 2))

codeforces 653B B. Bear and Compressing(dfs)

Codeforce 573A. Bear and Poker

[2016-04-04][codeforces][639][A][Bear and Displayed Friends]

codeforces 653C C. Bear and Up-Down(乱搞题)

[2016-04-04][codeforces][639][B][Bear and Forgotten Tree 3]