mysql数据库，根据id取每个id相对应钱数第二多的项目？问大神怎么写sql语句，要简单易懂的。谢谢。急

Posted 2023-05-06

SELECT * from tmp where total in(SELECT max(total) from tmp where total not in(SELECT max(total) from tmp GROUP BY id)GROUP BY id)

这是我建的表tmp,sql是可以取到每个id花钱第二的项目

结果：

看不清图片，sql看不懂的再提问

追问

你确定你可以取到？我把你sql语句的表和字段换成我这边的，还是多条啊

追答

你把你结果发给我看看

追问

追答

不太可能呀，我刚在我那张表又加了几条数据都可以的呀

有些怀疑你执行SQL只选择部分执行而已

不然我把我的表导给你？

好吧，我发现bug了，不好意思

追问

大神，搞定了吗？

追答

搞不定呀，我再试试

SELECT * from (SELECT * from tmp where i not in (select a.i from tmp as a where total = (select max(total) from tmp where a.id=id))
) as t where total=(SELECT max(total) from (SELECT * from tmp where i not in (select a.i from tmp as a where total = (select max(total) from tmp where a.id=id))
) as y where t.id=y.id)

我这i是表key来的

这可以的你看看能不能简化咯

DROP TABLE IF EXISTS `tmp`;CREATE TABLE `tmp` ( `i` int(3) NOT NULL AUTO_INCREMENT, `id` int(3) DEFAULT NULL, `typeid` varchar(3) DEFAULT NULL, `typename` varchar(20) DEFAULT NULL, `total` int(11) DEFAULT NULL, PRIMARY KEY (`i`)) ENGINE=InnoDB AUTO_INCREMENT=11 DEFAULT CHARSET=utf8;-- ------------------------------ Records of tmp-- ----------------------------INSERT INTO `tmp` VALUES ('1', '343', '08', '家用电器', '20540');INSERT INTO `tmp` VALUES ('2', '343', '06', '服装', '10920');INSERT INTO `tmp` VALUES ('3', '343', '07', '金属', '2250');INSERT INTO `tmp` VALUES ('4', '344', '08', '家用电器', '7680');INSERT INTO `tmp` VALUES ('5', '344', '07', '金属', '3200');INSERT INTO `tmp` VALUES ('6', '344', '06', '服装', '200');INSERT INTO `tmp` VALUES ('7', '343', '05', '生活日常', '12346');INSERT INTO `tmp` VALUES ('8', '343', '09', '餐饮', '1290');INSERT INTO `tmp` VALUES ('9', '344', '09', '餐饮', '12346');INSERT INTO `tmp` VALUES ('10', '344', '05', '生活日常', '7680');

这是表结构和数据

收到请回应一下

参考技术A select cgrant_id,sum(totalExpense) as total from table group by cgrant_id
图片看不太清楚，字段名和数据表名，你自己再做相应改变追问

不是根据每个id进行分组，你理解错误

如何用SQL SERVER取分组数据第一条

参考技术A

根据table1_id进行分组所得结果：

select * from (select a.id as a_id,a.name,a.time,a.content,b.id as b_id,b.user from table1 a inner join table2 b on a.id = b.table1_ID) new_tbl where b_id in (select min(id) from table2 group by table1_ID)

扩展资料：

注意事项

在SQL Server数据库中，使用top关键字：SELECT TOP number|percent column_name(s) FROM table_name

在MySQL数据库中，使用LIMIT关键字：SELECT column_name(s) FROM table_name LIMIT number

例子:SELECT * FROM Persons LIMIT 1 

select   bookName   from   book   where   price   >   20   limit   1; 

limit   1;
or
limit   0,1;

在Oracle数据库中，使用ROWNUM关键字：

SELECT column_name(s) FROM table_name WHERE ROWNUM <= number

例子:SELECT * FROM Persons WHERE ROWNUM <= 1