这会更短吗?
Posted
tags:
篇首语:本文由小常识网(cha138.com)小编为大家整理,主要介绍了这会更短吗?相关的知识,希望对你有一定的参考价值。
这段代码太长了。如何缩短它?非常3中3,这将出现在最后。 TxtDrawRemize.Text & = TxtResultStr1.Text + "" + TxtResultStr2.Text + "" + TxtResultStr3.Text & Environment.NewLine
我想这么做,我陷入了代码中,因为它太长了,有时候我会误解变量。如果你能帮助我,我将不胜感激。
Private Sub ScanareLinia1()
On Error Resume Next
Dim textsrtring As String = TxtStringNum1.Text
Dim words As String() = textsrtring.Split(" "c)
' Split string based on space
Dim found As Boolean = False
' Use For Each loop over words
Dim word As Integer
For Each word In words
For i As Integer = 0 To TxtIntDraws.Lines.Count - 1
If TxtIntDraws.Lines(1).Contains(word) Then
If Array.IndexOf(TxtIntDraws.Lines(1).Split(","c), CStr(word)) > -1 Then
TxtResultStr1.Text = word
End If
End If
Next
Next
End Sub
Private Sub ScanareLinia2()
On Error Resume Next
Dim textsrtring As String = TxtStringNum2.Text
Dim words As String() = textsrtring.Split(New Char() {" "c})
' Split string based on space
Dim found As Boolean = False
' Use For Each loop over words
Dim word As Integer
For Each word In words
For i As Integer = 0 To TxtIntDraws.Lines.Count - 1
If TxtIntDraws.Lines(1).Contains(word) Then
If Array.IndexOf(TxtIntDraws.Lines(1).Split(","c), CStr(word)) > -1 Then
TxtResultStr2.Text = word
End If
End If
Next
Next
End Sub
Private Sub ScanareLinia3()
On Error Resume Next
Dim textsrtring As String = TxtStringNum3.Text
Dim words As String() = textsrtring.Split(New Char() {" "c})
' Split string based on space
Dim found As Boolean = False
' Use For Each loop over words
Dim word As Integer
For Each word In words
For i As Integer = 0 To TxtIntDraws.Lines.Count - 1
If TxtIntDraws.Lines(1).Contains(word) Then
If Array.IndexOf(TxtIntDraws.Lines(1).Split(","c), CStr(word)) > -1 Then
TxtResultStr3.Text = word
End If
End If
Next
Next
TxtDrawRemize.Text &= TxtResultStr1.Text + " " + TxtResultStr2.Text + " " + TxtResultStr3.Text & Environment.NewLine
End Sub
Private Sub ScanareLinia4()
On Error Resume Next
Dim textsrtring As String = TxtStringNum1.Text
Dim words As String() = textsrtring.Split(New Char() {" "c})
' Split string based on space
Dim found As Boolean = False
' Use For Each loop over words
Dim word As Integer
For Each word In words
For i As Integer = 0 To TxtIntDraws.Lines.Count - 1
If Array.IndexOf(TxtIntDraws.Lines(2).Split(","c), CStr(word)) > -1 Then
TxtResultStr1.Text = word
End If
Next
Next
End Sub
Private Sub ScanareLinia5()
On Error Resume Next
Dim textsrtring As String = TxtStringNum2.Text
Dim words As String() = textsrtring.Split(New Char() {" "c})
' Split string based on space
Dim found As Boolean = False
' Use For Each loop over words
Dim word As Integer
For Each word In words
For i As Integer = 0 To TxtIntDraws.Lines.Count - 1
If Array.IndexOf(TxtIntDraws.Lines(2).Split(","c), CStr(word)) > -1 Then
TxtResultStr2.Text = word
End If
Next
Next
End Sub
Private Sub ScanareLinia6()
On Error Resume Next
Dim textsrtring As String = TxtStringNum3.Text
Dim words As String() = textsrtring.Split(New Char() {" "c})
' Split string based on space
Dim found As Boolean = False
' Use For Each loop over words
Dim word As Integer
For Each word In words
For i As Integer = 0 To TxtIntDraws.Lines.Count - 1
If Array.IndexOf(TxtIntDraws.Lines(2).Split(","c), CStr(word)) > -1 Then
TxtResultStr3.Text = word
End If
Next
Next
TxtDrawRemize.Text &= TxtResultStr1.Text + " " + TxtResultStr2.Text + " " + TxtResultStr3.Text & Environment.NewLine
End Sub
以上是关于这会更短吗?的主要内容,如果未能解决你的问题,请参考以下文章