简单吸引子

Posted 2021-02-26

Peter de Jong:
x' = sin(a * y) - cos(b * x)
y' = sin(c * x) - cos(d * y)
 
Cliff Pickover:
x' = sin(a * y) + c * cos(a * x)
y' = sin(b * x) + d * cos(b * y)