Remove Nth Node From End of List

Posted mqxnongmin

tags:

篇首语:本文由小常识网(cha138.com)小编为大家整理,主要介绍了Remove Nth Node From End of List相关的知识,希望对你有一定的参考价值。

题目

Given a linked list, remove the?nth?node from the end of list and return its head.

For example,

   Given linked list: 1->2->3->4->5, and n = 2.

   After removing the second node from the end, the linked list becomes 1->2->3->5.

Note:
Given?n?will always be valid.
Try to do this in one pass.

方法

使用两个指针进行标记。
	    public ListNode removeNthFromEnd(ListNode head, int n) {
	        ListNode p1 = head;
	        ListNode p2 = head;
	        for(int i = 0; i < n; i ++){
	            p2 = p2.next;
	        }
	        if(p2 == null){
	            head = head.next;
	        }else{
	            while(p2.next != null){
	                p1 = p1.next;
	                p2 = p2.next;
	            }
	             p1.next = p1.next.next;
	        }  
	        return head;
	    }


以上是关于Remove Nth Node From End of List的主要内容,如果未能解决你的问题,请参考以下文章

Remove Nth Node From End of List

19. Remove Nth Node From End of List

Remove Nth Node From End of List

Remove Nth Node From End of List

LC_19. Remove Nth Node From End of List

leetcode:Remove Nth Node From End of List