队列栈和递归遍历目录
Posted mjc69213
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栈
栈是一种内存结构,先进后出,后进先出。python中没有栈的概念,我们目前只能仿写。
# 模拟栈结构 stack = [] # 入栈(添加元素) stack.append("A") print(stack) stack.append("B") print(stack) stack.append("C") print(stack) #入栈顺序 A B C # 出栈(移除元素) stack.pop() print(stack) stack.pop() print(stack) #出栈顺序 C B A
队列
队列也是一种内存结构,先进先出,后进后出。
创建队列
import collections queue = collections.deque() # 进队(向队列中添加元素) queue.append("A") queue.append("B") queue.append("C") print(queue) # 出队(移除队列中的元素) queue.popleft() print(queue) queue.popleft() print(queue)
递归遍历目录和文件
import os path = r‘F:PycharmProjectsasic gram作业和习题 est‘ def getAllFileAndDir(path): # 获取当前目录下所有文件及文件目录 fileList = os.listdir(path) # print(fileList) # 遍历fileList列表 for fileName in fileList: # isdir isfile # print(fileName) # 拼接绝对路径 absFile = os.path.join(path,fileName) if os.path.isdir(absFile): print(absFile+‘---目录‘) getAllFileAndDir(absFile) else: print(absFile+‘---文件‘) getAllFileAndDir(path)
栈 深度遍历
import collections def getAllFileAndDir(sourcePath): stack = collections.deque() stack.append(sourcePath) while len(stack) != 0: path = stack.pop() fileList = os.listdir(path) for fileName in fileList: absFile = os.path.join(path, fileName) if os.path.isdir(absFile): print(absFile+‘---目录‘) stack.append(absFile) else: print(absFile+‘---文件‘) getAllFileAndDir(path)
队列 广度遍历
def getAllFileAndDir(sourcePath): queue = collections.deque() queue.append(sourcePath) while len(queue) !=0: path = queue.popleft() fileList = os.listdir(path) for fileName in fileList: absFile = os.path.join(path, fileName) if os.path.isdir(absFile): print(absFile+‘---目录‘) queue.append(absFile) else: print(absFile+‘---文件‘) getAllFileAndDir(path)
复制目录和文件
import os # 复制目录 def copyDir(sourDir,targetDir): if not os.path.exists(sourDir): print("如果源目录不存在,直接停止") return if not os.path.exists(targetDir): os.makedirs(targetDir) listName = os.listdir(sourDir) for dirNameAndFileName in listName: sourAbsPath = os.path.join(sourDir,dirNameAndFileName) targetAbsPath = os.path.join(targetDir,dirNameAndFileName) if os.path.isdir(sourAbsPath): copyDir(sourAbsPath,targetAbsPath) if os.path.isfile(sourAbsPath): # 如果目标文件不存在, 或者 如果该文件已经存在但是文件大小不一样 if (not os.path.exists(targetAbsPath)) or (os.path.exists(targetAbsPath) and (os.path.getsize(sourAbsPath) != os.path.getsize(targetAbsPath))): rf = open(sourAbsPath,"rb") wf = open(targetAbsPath,"wb") while True: content = rf.read(1024*1024) if len(content) == 0: break wf.write(content) wf.flush() wf.close() rf.close() sPath = r‘F:PycharmProjectsasic gram作业和习题 est‘ tPath = r‘F:PycharmProjectsasic gram作业和习题 estNew‘ copyDir(sPath, tPath)
文件复制实例
1.一个函数接受文件夹的名称作为输入参数,请将该文件夹中的所有文件复制到 文件夹名-副本 中去,请补充缺失的代码. (20分)
def copyFile(sPath)
2.题1复制过程中,每隔一秒打印一次复制进度(即当前已复制个数/总文件个数)(15分)
import os import collections import time import sys def getFileNum(sPath): num = 0 stack = collections.deque() stack.append(sPath) while len(stack) != 0: path = stack.pop() fileList = os.listdir(path) for fileName in fileList: absFile = os.path.join(path, fileName) if os.path.isdir(absFile): stack.append(absFile) else: num += 1 return num def copyFile(sPath): tPath = r‘F:PycharmProjectsasic gram作业和习题Anaconda3-副本‘ stack1 = collections.deque() stack1.append(sPath) stack2 = collections.deque() stack2.append(tPath) timepoint = 1 filenum = 0 while len(stack1) != 0: sPath = stack1.pop() tPath = stack2.pop() if not os.path.exists(tPath): os.makedirs(tPath) listName = os.listdir(sPath) for filename in listName: absfile = os.path.join(sPath, filename) tabsfile = os.path.join(tPath, filename) if os.path.isdir(absfile): stack1.append(absfile) stack2.append(tabsfile) else: rf = open(absfile, ‘rb‘) wf = open(tabsfile, ‘wb‘) while True: content = rf.read(1024*1024) if len(content) == 0: break wf.write(content) # 刷新缓冲区 wf.flush() if time.clock()//1 == timepoint: sys.stdout.write(‘ 进度:%d/%d‘%(filenum,num)) timepoint += 1 wf.close() rf.close() filenum += 1 sys.stdout.write(‘ 进度:%d/%d‘ % (num, num)) sPath = r‘F:PycharmProjectsasic gram作业和习题Anaconda3‘ num = getFileNum(sPath) # print(num) start_time = time.clock() copyFile(sPath)
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