1036 Boys vs Girls

Posted 2020-12-19 ruruozhenhao

This time you are asked to tell the difference between the lowest grade of all the male students and the highest grade of all the female students.

Input Specification:

Each input file contains one test case. Each case contains a positive integer N, followed by N lines of student information. Each line contains a student‘s name, gender, ID and grade, separated by a space, where name and ID are strings of no more than 10 characters with no space, gender is either F (female) or M (male), and grade is an integer between 0 and 100. It is guaranteed that all the grades are distinct.

Output Specification:

For each test case, output in 3 lines. The first line gives the name and ID of the female student with the highest grade, and the second line gives that of the male student with the lowest grade. The third line gives the difference grade?F??−grade?M??. If one such kind of student is missing, output Absent in the corresponding line, and output NA in the third line instead.

Sample Input 1:

3
Joe M Math990112 89
Mike M CS991301 100
Mary F EE990830 95

 

Sample Output 1:

Mary EE990830
Joe Math990112
6

 

Sample Input 2:

1
Jean M AA980920 60

 

Sample Output 2:

Absent
Jean AA980920
NA

题意：

　　找出女生的最高成绩和男生的最低成绩，并输出两者之差。

思路：

　　模拟

Code：

 1 #include <bits/stdc++.h>
 2 
 3 using namespace std;
 4 
 5 struct Stu {
 6     string name;
 7     char gender;
 8     string id;
 9     int grade;
10 };
11 
12 bool cmp1(Stu s1, Stu s2) { return s1.grade < s2.grade; }
13 
14 bool cmp2(Stu s1, Stu s2) { return s1.grade > s2.grade; }
15 
16 int main() {
17     int n;
18     cin >> n;
19     vector<Stu> male, female;
20     for (int i = 0; i < n; ++i) {
21         string name, id;
22         char gender;
23         int grade;
24         cin >> name >> gender >> id >> grade;
25         if (gender == ‘F‘)
26             female.push_back({name, gender, id, grade});
27         else
28             male.push_back({name, gender, id, grade});
29     }
30     sort(female.begin(), female.end(), cmp2);
31     sort(male.begin(), male.end(), cmp1);
32     if (female.size() > 0)
33         cout << female[0].name << " " << female[0].id << endl;
34     else
35         cout << "Absent" << endl;
36     if (male.size() > 0)
37         cout << male[0].name << " " << male[0].id << endl;
38     else
39         cout << "Absent" << endl;
40     if (female.size() > 0 && male.size() > 0)
41         cout << female[0].grade - male[0].grade << endl;
42     else
43         cout << "NA" << endl;
44     return 0;
45 }