钻石和玻璃球游戏(钻石位置不固定)

Posted 2020-12-06 hany-postq473111315

import random

def no_change(times):
    glass_ball = 0
    diamond = 0
    times2=times
    while times>0:
        drawers={‘drawer1‘: False, ‘drawer2‘: False, ‘drawer3‘: False}
        drawer_with_diamond=random.randint(1,3)  #获取随机数1-3
        drawers[‘drawer%d‘%drawer_with_diamond]=True  #随机在3个抽屉中放入钻石
        your_choice=random.randint(1,3) #再次获取随机数1-3
        what_you_get=drawers[‘drawer%d‘%your_choice]
        if what_you_get==False:  #判定选到的是什么
            glass_ball+=1
        else:
            diamond+=1
        times-=1
    winning_rate=diamond/(diamond+glass_ball)  #获取赢得钻石的概率
    print(‘一共试验了%d次，你获得钻石的概率为%f‘%(times2, winning_rate))

def change_drawer(times):
    glass_ball = 0
    diamond = 0
    times2=times
    while times>0:
        drawers = {‘drawer1‘: False, ‘drawer2‘: False, ‘drawer3‘: False}
        drawer_with_diamond = random.randint(1, 3)  # 获取随机数1-3
        drawers[‘drawer%d‘ % drawer_with_diamond] = True  # 随机在3个抽屉中放入钻石
        your_choice = random.randint(1, 3)  # 再次获取随机数1-3
        your_drawer=‘drawer‘+str(your_choice)
        for things in drawers:
            if drawers[things] == True: #获取钻石在第几个抽屉中
                if things==your_drawer: #如果此时你选的，正是有钻石的那个抽屉，并且你换抽屉，那么你必然拿到玻璃球
                    glass_ball+=1
                if things!=your_drawer: #如果此时你选的，是有玻璃球的，主持人给你展示另一个有玻璃球的的，你换抽屉，必然拿到钻石
                    diamond+=1
        times-=1
    winning_rate=diamond/(diamond+glass_ball)  #获取赢得钻石的概率
    print(‘一共试验了%d次，你获得钻石的概率为%f‘ % (times2, winning_rate))

def main():
    change_or_not=str(input(‘你选择换还是不换抽屉？换/不换:‘))
    if change_or_not==‘换‘:
        times=int(input(‘请输入你想试验的次数：‘))
        change_drawer(times)
    else:
        times = int(input(‘请输入你想试验的次数：‘))
        no_change(times)

if __name__==‘__main__‘:
    main()

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2020-05-27