python内置函数zip

Posted 2020-09-09

接收两个或多个序列，并返回一个元组列表，并且每个元组列表包含来自每个序列中的第一个元素

s = "abc"
t = [11,23,45]
print(zip(s,t))
for pair in zip(s,t):
    print(pair)

print(list(zip(s,t)))

D:\Python\Python35\python.exe D:/PycharmProjects/helloworld/src/zipTest.py
<zip object at 0x00000201D6459648>
(‘a‘, 11)
(‘b‘, 23)
(‘c‘, 45)
[(‘a‘, 11), (‘b‘, 23), (‘c‘, 45)]

Process finished with exit code 0

zip的序列长度不同，则取短的那个。

数量不相同:t长度大于s

s = "abc"
t = [11,23,45,77,88]
print(zip(s,t))
for pair in zip(s,t):
    print(pair)

print(list(zip(s,t)))

D:\Python\Python35\python.exe D:/PycharmProjects/helloworld/src/zipTest.py
<zip object at 0x00000252DE5B96C8>
(‘a‘, 11)
(‘b‘, 23)
(‘c‘, 45)
[(‘a‘, 11), (‘b‘, 23), (‘c‘, 45)]

Process finished with exit code 0

数量不相同，s长度大于t

s = "abcer"
t = [11,23,45]
print(zip(s,t))
for pair in zip(s,t):
    print(pair)

print(list(zip(s,t)))

D:\Python\Python35\python.exe D:/PycharmProjects/helloworld/src/zipTest.py
<zip object at 0x0000024C7E2C9648>
(‘a‘, 11)
(‘b‘, 23)
(‘c‘, 45)
[(‘a‘, 11), (‘b‘, 23), (‘c‘, 45)]

Process finished with exit code 0