python 异步编程 asyncio

Posted 2021-02-28

import datetime
import time
import asyncio
import numba as nb
import numpy as np

@nb.jit()
def f(n):
    if n<2:
        return 1
    else:
        return f(n-1)+f(n-2)

async def fun(m):
    asyncio.sleep(0.1)
    return ‘输出{}‘.format(i)

loop = asyncio.get_event_loop()

st = time.time()

for i in  range(41000):
    s = loop.run_until_complete(fun(i))
    # print(s,‘  ‘,time.strftime(‘%Y-%m-%d %H:%M:%S‘,time.localtime()))

st2 = time.time()
print(‘异步编程用时:‘,st2-st,‘ s‘)

def fun2(m):
    time.sleep(0.1)
    return ‘输出{}‘.format(i)



for i in range(41):
    s = fun2(i)
    # print(s, ‘  ‘, time.time())

print(‘同步编程用时:‘,time.time()-st2,‘ s‘)